The number of content changes to a Web site follows a Poisson distribution with a mean of 0.18 per day. a) What is the probability of two or more changes in a day? Round your answer to four decimal places (e.g. 98.7654). P = i b) What is the probability of no content changes in five days? Round your answer to four decimal places (e.g. 98.7654). P = i c) What is the probability of two or fewer changes in five days? Round your answer to four decimal places (e.g. 98.7654). P = i

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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The number of content changes to a Web site follows a Poisson distribution with a mean of 0.18 per day.
a) What is the probability of two or more changes in a day?
Round your answer to four decimal places (e.g. 98.7654).
P = i
b) What is the probability of no content changes in five days?
Round your answer to four decimal places (e.g. 98.7654).
P = i
c) What is the probability of two or fewer changes in five days?
Round your answer to four decimal places (e.g. 98.7654).
P =
i
Transcribed Image Text:The number of content changes to a Web site follows a Poisson distribution with a mean of 0.18 per day. a) What is the probability of two or more changes in a day? Round your answer to four decimal places (e.g. 98.7654). P = i b) What is the probability of no content changes in five days? Round your answer to four decimal places (e.g. 98.7654). P = i c) What is the probability of two or fewer changes in five days? Round your answer to four decimal places (e.g. 98.7654). P = i
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