The Null hypothesis is: [ Select ]The Sum of Products for the two variables is: [ Select]The degrees of freedom (df) for the test is: [ Select ]The value of the numerator of the t-test formula is: [ Select ]The value of the denominator of the t-test formula is: [ Select ]The critical value is: [ Select ]> I am interested seasonal affective disorder (SAD) and in the relationship between number of sunnydays per month and mood survey measures. I collected some data on myself by counting thenumber of sunny days for the months between September and March and also taking a "happiness"inventory to measure my lack of depression on the 15th of each of those months. The data are inthe chart below.MonthSunny Days HappinessSep1575Oct1782Nov1154Dec51Jan1047Feb1263Mar1564Go through the steps of hypothesis testing to determine if there was a significant relationshipbetween the "sunny days" and "happiness" variables. Use alpha = .05. Answer the following

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For the T-test of the dependent means, In this problem, your test subjects have undergone a study skills training session after taking the first quiz (Quiz 1). Does quiz 1 perform better on quiz 2? Are quiz 1 and quiz 2 a significantly different? How do you state the hypothesis and then decide based on the t-test if we should reject the null hypothesis?
Total blood volume (In ml) per body welght (In kg) is Important In medical research. For healthy adults, the red blood cell volume mean is about u = 28 ml/kg.t Red blood cell volume that is too low or too high can Indicate a medical problem. Suppose that Roger has had seven blood tests, and the red blood cell volumes were as follows. 32 26 40 37 31 35 29 Let x be a random varlable that represents Roger's red blood cell volume. Assume that x has a normal distribution and o = 4.75. Do the data Indicate that Roger's red blood cell volume is different (either way) from u = 28 ml/kg? Use a 0.01 level of significance. (a) what is the level of significance? State the null and alternate hypotheses. Will you use a left-talled, nght-taled, or two-talled test? O Ho: H= 28 ml/kg; H: H> 28 ml/kg; right-tailed O Hg: H- 28 ml/kg; H: u = 28 ml/kg; two-taled O Ho: H- 28 m/kg; H: H 23 2$ backspace 1 4. 8 9.
Check conditions for the Chi-Square test for independence: The number of people who survived the titanic based on class and sex is collected and attached in the photo. Null: class and sex of a person who survived the titanic are independent. Alt: class and sex of a person who survived the titanic are dependent.
A certain affects virus 0.8% of the population. A test used to detect the virus in a person is positive 88% of the time if the person has the virus (true positive) and 13% of the time if the person does not have the virus (false postive). Fill out the remainder of the following table and use it to answer the two questions below. (enter answer with no commas, i.e. as 1000 not 1,000.) Infected Not Infected Total Positive Test [a] [b] [c] Negative Test [d] [e] [f] Total 800 99,200 100,000 i) Find the probability that a person has the virus given that they have tested positive. (Round your answer to the nearest tenth of a percent and do not include a percent sign.)[g]_______ % ii) Find the probability that a person does not have the virus given that they test negative. (Round your answer to the nearest tenth of a percent and do not include a percent sign.)[h]________ %
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Using the accompanying New Account Processing data, perform chi-square tests for independence to determine if certification is independent of gender and if certification is independent of having prior industry background. Click the icon to view the New Account Processing data. - x Find the hypotheses for the chi-square test for independence to determine if certification is independent of gender. H: Certification and Gender are independent New Account Processing Data H₁ Certification and Gender are dependent Perform the chi-square test for independence to determine if certification is independent of gender. Compute the chi-square statistic. (Type an integer or decimal rounded to two decimal places as needed.) Gender Certified Prior Background M Y F Y Y M Y N N Y M F N Y Y Y Y Y Y N N F N Y M Y N M Y N F N Y N N F N Y M Y Y M N Y M N N M N Y Print Done
Dysart's is interested in whether the average check size is more or less than before the pandemic, when the average per check was $14. Select the v 14 [ Select ] correct symbols to use in the alternate hypothesis for this hypothesis test. Ha: [ Select ]
Find the p-value
In a study of pain relievers, 50 people were given product A, and 40 experienced relief. In the same study, 100 people were given product B, and 89 experienced relief. Fill in the blanks below to make the most reasonable statement possible. Product (Choose one) performed better in the study. That is because only% failed to get relief with this product, whereas failed to get relief with Product (Choose one) ▼ X S Esp i ! A M
Which of the following can be assessed by a dependent T-Test? Group of answer choices the score means of two distinct group the score means of pre and post tests from same participants the score means of three distinct group
An experimental design for a paired t test has 28 pairs of identical twins. How many degrees of freedom are there in this t test? There are degrees of freedom. (simplify your answer)
A researcher rejected the null where r(56) = .050, p = .27. Was the researcher correct in rejecting the null? Group of answer choices Yes No

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The Null hypothesis is: [ Select] The Sum of Products for the two variables is: [ Select] The degrees of freedom (df) for the test is: [ Select] The value of the numerator of the t-test formula is: [ Select 1