The null and alternate hypotheses are:He : Hd soна: на>0The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sampleof 4 days last month.Day2134Day shift.11 12 13 19Afternoon shift 9 10 14 15At the 0.03 significance level, can we conclude there are more defects produced on the day shift? Hint. For the calculations, assumethe day shift as the first sample.Required:a. What is the p-value? NOTE: P-value calculators are available through online search. (Round your answer to 4 decimal places.)p-value

The question is about hypothesis testing.Given :Null and alternative hypothesis :Data :To find :Is…

Answered: The null and alternate hypotheses are:…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a.)What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = b.)What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to four decimal places.)p-value =
Please do not use/copy other's answer especially on chegg. Please answer this one using your own answer
(5). Calculate SS, variance and standard deviation for the following sample of n=7 scores: 8, 6, 5, 2, 6, 3, 5.
. The term sample usually refers to a sample that ___ - Consists of people with chemical dependency problems - Uses the same group of individuals with a before/after measurement - Requires a dependent variable for hypothesis testing - Is randomly selected from two dependent populations
A) What is the mean difference score, MD? (Hint: fill in the difference column using TMS - minus - Sham) a. 4 b. 5 c. 20 d. 4.2 B) What is the sample variance, s2, for the difference scores? a. 7.2 b. -9 c. 8.5 d. 9
Given below are the analysis of variance (ANOVA) results from a Minitab display. Assume that you want to use a 0.01 significance level in testing the null hypothesis that the samples come from populations with the same mean. Source DF SS MS F P-val Factor 2. 2280.0 1140.0 7.9 5.39E–04 Error 144 20691.7 143.7 Total 146 22971.8 What can you conclude about the equality of the population means? (circle one) Reject H0 since the p-value is greater than the significance level. Fail to reject H0 since the p-value is greater than the significance level. Reject H0 since the p-value is less than the significance level. Fail to reject H0 since the p-value is less than the significance level.
The average family size was reported as 7.2. A random sample of families in a particular school district resulted in the following family sizes: Size 4 9. 8. 4 8 9 At 1% level of significance, does the average family size different from the national average? Use traditional way of testing hypothesis. a. Mean family size of the sample: b. Sample variance: ct Test Value: d. Summarize your Interpretation: 4)
calculate ss variance and standard deviation for the following population of N=5 scores: 2,13,4,10,6
Class 1 Final Sample Size: 30 Sample Variance: 80.55 Sample Mean: 44.2917 Class 2 Final Sample Size:30 Sample Variance: 55.29 Sample Mean: 36.4833 The assignment says to use the Z test for means and assume the hypothesized difference is 0. 1. Is there a significant difference in the means of the two finals at the .01 level of significance? 2. Why or why not?
For a two-tailed test with a sample size of 17 and a 0.20 level of significance, the t value is O a. 1.337 O b. 0.865 O c. 1.230 d. 1.734 O
1. The tables below show the results of an independent samples t-test in SPSS conducted using the SPSS data we have been using this semester. Two groups ("Yes" and "No") are compared on their "final". Yes and no refer to whether they attended the review sessions or not. Review the results carefully and answer the questions below. (12 points) final final Attended review sessions? No Yes Equal variances assumed Equal variances not assumed Levene's Test for Equality of Variances F Group Statistics 219 Sig. N .641 35 70 t -2.693 d. What are the df for the t-test we use? 103 Mean Independent Samples Test -2.719 59.83 64.14 Std. Deviation 7.591 7.810 df Sig. (2-tailed) 103 .008 69.872 .008 e. Are the groups significantly different from each other? f. Which group scored higher? Yes Group No Group The two groups are not significantly different_ t-test for Equality of Means Mean Difference -4.314 Std. Error Mean -4.314 1.283 .933 Std. Error Difference 1.602 1.587 95% Confidence Interval of the…
Given below are the analysis of variance results from a stat software display comparing sample data for the meanmileage for 4 different types of cars. Assume that you want to use a 0.05 significance level in testing the null hypothesisthat the different samples come from cars with the same mileage. What can you conclude about the equality of the population means?Source DF SS MS F pFactor 3 13.500 4.500 5.17 0.011Error 16 13.925 0.870Total 19 27.425 12)What is the null and alternative hypothesis for this scenari?Based on this One Way Anova software analysis, would you reject of fail to reject the nul hypothesis?What does this result mean in context?

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