The null and alternate hypotheses are:He: HasoH₁: Ha> 0The following sample Information shows the number of defective units produced on the day shift and the afternoon shift for a sampleof 4 days last month.Day shiftAfternoon shift11110p-valueDay2At the 0.03 significance level, can we conclude there are more defects produced on the day shift? Hint. For the calculations, assumethe day shift as the first sample.Required:a. What is the p-value? NOTE: P-value calculators are available through online search. (Round your answer to 4 decimal places.)341014199 14 16O Do not reject HeO Reject Heb. What is your decision regarding the null hypothesis?c. What is the conclusion indicated by the analysis?There are more defective parts produced on the day shift.

The null and alternative hypotheses are:The test is right-tailed.

Answered: The null and alternate hypotheses are:…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A high school conducts a dependent sample experiment to test if there is a difference between the number of times students are absent in the fall and winter months. You have data for the following 5 students: STUDENT FALL WINTER 1 2 3 4 5 2 0 1 2 O What do you conclude about this school's absences? (Assume standard a = 0.05) 2 1 2 4 T O There is no difference between the Fall and Winter months. O There is a statistically significant difference between the Fall and Winter months. There is a difference but it is only somewhat statistically significant. There is not enough data to determine if there is a difference in absences.
. 3. A researcher is interested in knowing if preterm infants with late metabolic acidosis and preterm infants without the condition differ with respect to urine levels of a certain chemical. The mean levels, standard deviations, and sample sizes from the two samples are given below. Assuming that the populations have equal variances: a. Fill in the missing pieces of the Stata output. ttesti 38 8.5 3.5 32 6.85 2.6 X y Two-sample t test with A variances combined diff Obs Ho: diff=0 38 32 Sample With condition 70 diff mean(x) n 38 Without condition 32 Ha: diff |t|) = F [95% Conf. Intervall 7.349579 5.9126 6.98079 .1552544 t = degrees of freedom = 9.650421 7.7874 8.510638 3.144746 E b. What is the conclusion of your test? c. Use this output to construct a 99% confidence interval for the difference between the two means. 68 Ha: diff0 Pr(Tt) = 0.0155
1. The tables below show the results of an independent samples t-test in SPSS conducted using the SPSS data we have been using this semester. Two groups ("Yes" and "No") are compared on their "final". Yes and no refer to whether they attended the review sessions or not. Review the results carefully and answer the questions below. (12 points) final final Attended review sessions? No Yes Equal variances assumed Equal variances not assumed Levene's Test for Equality of Variances F Group Statistics 219 Sig. N .641 35 70 t -2.693 d. What are the df for the t-test we use? 103 Mean Independent Samples Test -2.719 59.83 64.14 Std. Deviation 7.591 7.810 df Sig. (2-tailed) 103 .008 69.872 .008 e. Are the groups significantly different from each other? f. Which group scored higher? Yes Group No Group The two groups are not significantly different_ t-test for Equality of Means Mean Difference -4.314 Std. Error Mean -4.314 1.283 .933 Std. Error Difference 1.602 1.587 95% Confidence Interval of the…
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O.3. Question Help A group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below. Use a 0.10 significance level to test the claim that these times are from a population with a mean equal to 60 seconds. Does it appear that students are reasonably good at estimating one minute? 66 80 37 66 45 22 62 66 65 45 64 73 94 91 63 O Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? O A. Ho: u= 60 seconds H:µ#60 seconds O B. Ho: H= 60 seconds H4:µ 60 seconds O D. Ho: u#60 seconds H:µ = 60 seconds Click to select your answer and then click Check Answer. ? 3 3 parts remaining Clear All Check Answer MacBook 888 DD esc. F7 F8 F9 F10 F11 F12 F3 F4 F5 F6 F1 @ $ & 1 2 4 5 7 8 Q W E R. T Y tab A S G J K os lock C V B # 3
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Question II. The following two-by-three table gives the sample proportions corresponding to different combinations of factor categories (for example, 28% of the sample fell in the cell representing category 1 of factor A and category 3 of factor B). A B .13 .19 .28 .07 .11 .22 II(a). Suppose that the sample size is n=100. Carry out a chi-squared test of independence at the 10% significance level. Make sure to state the null and alternative hypotheses, degrees of freedom, the value of your test statistic, the p-value, and the final conclusion. II(b). Now, suppose that n=1000 and repeat part 3(a). II(c). Find the smallest value of n that will result in rejection of the null hypothesis of part 3(a) at 10% level. Start by finding the appropriate x² statistic (which will depend on the n).

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