The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 10 16 17 Afternoon shift 9 10 14 15 At the 0.100 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample. State the decision rule. (Round your answer to 2 decimal places.) Compute the value of the test statistic. (Round your answer to 3 decimal places.) What is the p-value? multiple choice 1 Between 0.025 and 0.05 Between 0.001 and 0.005 Between 0.005 and 0.01 What is your decision regarding H0? multiple choice 2 Reject H0 Do not reject H0
The null and alternate hypotheses are: H0 : μd ≤ 0 H1 : μd > 0 The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month. Day 1 2 3 4 Day shift 10 10 16 17 Afternoon shift 9 10 14 15 At the 0.100 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample. State the decision rule. (Round your answer to 2 decimal places.) Compute the value of the test statistic. (Round your answer to 3 decimal places.) What is the p-value? multiple choice 1 Between 0.025 and 0.05 Between 0.001 and 0.005 Between 0.005 and 0.01 What is your decision regarding H0? multiple choice 2 Reject H0 Do not reject H0
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
The null and alternate hypotheses are:
H0 : μd ≤ 0
H1 : μd > 0
The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.
| Day | ||||
| 1 | 2 | 3 | 4 | |
| Day shift | 10 | 10 | 16 | 17 |
| Afternoon shift | 9 | 10 | 14 | 15 |
At the 0.100 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample.
-
State the decision rule. (Round your answer to 2 decimal places.)
-
Compute the value of the test statistic. (Round your answer to 3 decimal places.)
-
What is the p-value?
multiple choice 1
-
Between 0.025 and 0.05
-
Between 0.001 and 0.005
-
Between 0.005 and 0.01
-
What is your decision regarding H0?
multiple choice 2
-
Reject H0
-
Do not reject H0
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