The normal human body temperature is T= 310 K. At what wavelength would humans emit the blackbody radiation? What region of the electromagnetic spectrum does it correspond to?

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Question 4 please 

1. Plot ipeak Vs 1/T using the scatter plot as you did in the previous experiment. Make a
linear fit of the data (add a linear trendline) by selecting the intercept at zero. Display an
equation of this fit on the chart. What value of “b" do you get? (Attach your plot to this
lab report).
b =
um-K
2. Calculate the discrepancy error, |b - 2898|/ 2898 × 100% and comment about your
finding. Does it agree with the theoretical value?
3. Using your value of b and the Wien's Displacement equation, predict the surface
temperature of a neutron star whose peak wavelength is observed in the x-ray region of
A peak = 0.001 µm.
T =
K
4. The normal human body temperature is T= 310 K. At what wavelength would humans
emit the blackbody radiation? What region of the electromagnetic spectrum does it
correspond to?
hum
um.
5. Can you now explain why blue stars hotter than the red stars?
Transcribed Image Text:1. Plot ipeak Vs 1/T using the scatter plot as you did in the previous experiment. Make a linear fit of the data (add a linear trendline) by selecting the intercept at zero. Display an equation of this fit on the chart. What value of “b" do you get? (Attach your plot to this lab report). b = um-K 2. Calculate the discrepancy error, |b - 2898|/ 2898 × 100% and comment about your finding. Does it agree with the theoretical value? 3. Using your value of b and the Wien's Displacement equation, predict the surface temperature of a neutron star whose peak wavelength is observed in the x-ray region of A peak = 0.001 µm. T = K 4. The normal human body temperature is T= 310 K. At what wavelength would humans emit the blackbody radiation? What region of the electromagnetic spectrum does it correspond to? hum um. 5. Can you now explain why blue stars hotter than the red stars?
T (K)
1/T (K*l)
ipeak (um)
500
203
103
1000
5.796
1500
2.898
6.66-04
s-04
3.33-04
2.504
2000
1.932
3000
1.449
4000
0.966
6000
0.724
10,000
1.66-04
0.483
104
0.290
Transcribed Image Text:T (K) 1/T (K*l) ipeak (um) 500 203 103 1000 5.796 1500 2.898 6.66-04 s-04 3.33-04 2.504 2000 1.932 3000 1.449 4000 0.966 6000 0.724 10,000 1.66-04 0.483 104 0.290
Expert Solution
Fundamentals

Wein's Law says that different objects at different temperatures emit different wavelength peaks. It is given as:
λmT=b(1)
where,
λm is the peak wavelength.
T is the Temperature of the object.
b is a constant, called the Wein's Displacement Constant =2.898×10-3 m K=2898 μm K.

This implies, the higher the temperature, the lower will be the peak.

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