The Normal Distribution Activity For Data Set 3 Variance = Mean = 8.33 0.8427 Standard Deviation = 0.9180 13. Sketch the third bell curve by showing the mean and standard deviation. S.SN 1.N 14. What are the data values (raw scores) associated with standard scores of -1.05 and -0.05? Determine the percentage in between these scores. Draw the curve and show your complete solution. A ea The percentage that is in between the raw scores of 7.3661 and 8.2841 is 33.32%. 15. What are the data values (raw scores) associated with standard scores of -0.09 and 1.15? Determine the percentage in between these scores. Draw the curve and show your complete solution. t 0. in The percentage that is in between the raw scores of 8.2474 and 9.3857 is 33.9%.

MATLAB: An Introduction with Applications
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Chapter1: Starting With Matlab
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answer 13 14 15 HANDWRITTTEN

10. What is the range (_<x<_) of the data values that would allow 71% of the data to fall
within the mean observing symmetry? Draw the curve and show your complete solution.
The Normal Distribution Activity
For Data Set 3
A- 71%
0.3550 ; 2: :1.06
• 0.7100
A2 :
0. 3550 ; z • 1.06
Mean =
8.33
Variance =
0.8427
Standard Deviation =
0.9180
WHEN 2- 1. O G
WHEN E -1. 0
THE RANCE OF THE DATA UALUES
THAT QILL ALLOW 71 OF THE DATA
TO FALL WITHIN THE MEAN OBSERUING
SYMMETRY IS .0.2552SX 4 Y.1552
1.0G : *- 2.
13. Sketch the third bell curve by showing the mean and standard deviation.
1.OG : x- 2
2.1815
2.1175
-2. 2552 = x-2
*0.2652
2.2562 : A - 2
-1.G
J.G
*- y. 2552
The range of data values that will allow 71% of the data to fall within the mean of symmetry is -
0.2552 and 4.2552.
11. What is the variance of this data set?
o² = (2.1275)²
o2 = 4.5263
Given that the standard deviation is 2.1275 and it is the square root of the variance,
5.576
6. 494
8.33
9. 248 10.166H.084
the value of the variance is 4.5263.
12. Are there any outliers with this data set? (Outliers refer to data points that lie beyond 3
standard deviation from the mean).
14. What are the data values (raw scores) associated with standard scores of -1.05 and -0.05?
Determine the percentage in between these scores. Draw the curve and show your complete
solution.
A-0. os czco = 0. 0le9
There is only one outlier with this data set (i.e. 9) while the remaining values in the data
set do not go beyond the three standard deviations from the mean.
-1.05 - * -. 33
-0. 05 : *-F.B
A-1-05 caL-0.o5 = 0.35 3) -0.0199
-0.9639 e x-E 33
-0.0459 = a - t.33
= 0. 3332
THE PERCENTA CE IN BETWEEN IS 33.32 %
x= t. 2841
X= 7. 366)
-1-05 -0.5 0
The percentage that is in between the raw scores of 7.3661 and 8.2841 is 33.32%.
15. What are the data values (raw scores) associated with standard scores of -0.09 and 1.15?
Determine the percentage in between these scores. Draw the curve and show your complete
solution.
A.0.09 ceLo = 0.0s59
- 0.09 = x - (.33
1. IS x-t.37
0. qiro
A.0.o9 cteI.IS - 0. 3949 -0.0359
= 0. 934
THE PEECENTACE IN BETWEEN IS 33. 9 2
1-os57 1-t83
- 0-0 e 26 : X - P.33
*e 9.3r57
* - f.2474
-0,09 0 1.Is
The percentage that is in between the raw scores of 8.2474 and 9.3857 is 33.9%.
Transcribed Image Text:10. What is the range (_<x<_) of the data values that would allow 71% of the data to fall within the mean observing symmetry? Draw the curve and show your complete solution. The Normal Distribution Activity For Data Set 3 A- 71% 0.3550 ; 2: :1.06 • 0.7100 A2 : 0. 3550 ; z • 1.06 Mean = 8.33 Variance = 0.8427 Standard Deviation = 0.9180 WHEN 2- 1. O G WHEN E -1. 0 THE RANCE OF THE DATA UALUES THAT QILL ALLOW 71 OF THE DATA TO FALL WITHIN THE MEAN OBSERUING SYMMETRY IS .0.2552SX 4 Y.1552 1.0G : *- 2. 13. Sketch the third bell curve by showing the mean and standard deviation. 1.OG : x- 2 2.1815 2.1175 -2. 2552 = x-2 *0.2652 2.2562 : A - 2 -1.G J.G *- y. 2552 The range of data values that will allow 71% of the data to fall within the mean of symmetry is - 0.2552 and 4.2552. 11. What is the variance of this data set? o² = (2.1275)² o2 = 4.5263 Given that the standard deviation is 2.1275 and it is the square root of the variance, 5.576 6. 494 8.33 9. 248 10.166H.084 the value of the variance is 4.5263. 12. Are there any outliers with this data set? (Outliers refer to data points that lie beyond 3 standard deviation from the mean). 14. What are the data values (raw scores) associated with standard scores of -1.05 and -0.05? Determine the percentage in between these scores. Draw the curve and show your complete solution. A-0. os czco = 0. 0le9 There is only one outlier with this data set (i.e. 9) while the remaining values in the data set do not go beyond the three standard deviations from the mean. -1.05 - * -. 33 -0. 05 : *-F.B A-1-05 caL-0.o5 = 0.35 3) -0.0199 -0.9639 e x-E 33 -0.0459 = a - t.33 = 0. 3332 THE PERCENTA CE IN BETWEEN IS 33.32 % x= t. 2841 X= 7. 366) -1-05 -0.5 0 The percentage that is in between the raw scores of 7.3661 and 8.2841 is 33.32%. 15. What are the data values (raw scores) associated with standard scores of -0.09 and 1.15? Determine the percentage in between these scores. Draw the curve and show your complete solution. A.0.09 ceLo = 0.0s59 - 0.09 = x - (.33 1. IS x-t.37 0. qiro A.0.o9 cteI.IS - 0. 3949 -0.0359 = 0. 934 THE PEECENTACE IN BETWEEN IS 33. 9 2 1-os57 1-t83 - 0-0 e 26 : X - P.33 *e 9.3r57 * - f.2474 -0,09 0 1.Is The percentage that is in between the raw scores of 8.2474 and 9.3857 is 33.9%.
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