The next three (3) problems deal with the titration of 501 mL of 0.501 M carbonic acid (H₂CO3) (KalWhat is, the pH of the solution at the 2nd equivalence point? 11.86avada=4.3 x 10-7, Kaz = 5.6 x 10-11) with 1.5 M KOH.What will the pH of the solution be when 0.2928 L of 1.5 M KOH are added to the 501 mL of 0.501 M carbonic acid? 10.73How many mL of the 1.5 M KOH are needed to raise the pH of the carbonic acid solution to a pH of 6.635? 67.7

Answered: Image /qna-images/answer/6b201552-99ca-405b-b064-fe1391d9b88e.jpg

The next three (3) problems deal with the titration of 501 mL of 0.501 M carbonic acid (H₂CO3) (Ka1 = 4.3 x 10-7, Ka2 = 5.6 x 10-11) with 1.5 M KOH. What is, the pH of the solution at the 2nd equivalence point? 11.86 vada What will the pH of the solution be when 0.2928 L of 1.5 M KOH are added to the 501 mL of 0.501 M carbonic acid? 10.73

The next three (3) problems deal with the titration of 501 mL of 0.501 M carbonic acid (H₂CO3) (Ka1 = 4.3 x 10-7, Ka2 = 5.6 x 10-11) with 1.5 M KOH. What is, the pH of the solution at the 2nd equivalence point? 11.86 vada What will the pH of the solution be when 0.2928 L of 1.5 M KOH are added to the 501 mL of 0.501 M carbonic acid? 10.73

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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