A 500.0 mL buffer solution is 0.150M in acetic acid (Ka = 1.8 x 10-5) and 0.350M in sodium acetate. What is the pH of the solution before and after adding 0.0026 mol of NaOH? (Assume the volume of the buffer does not change)

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A 500.0 mL buffer solution is 0.150M in acetic acid (Ka = 1.8 x 10-5) and 0.350M in sodium acetate. What is the pH of the solution before and after adding 0.0026 mol of NaOH? (Assume the volume of the buffer does not change)

Expert Solution
Step 1

Acetic acid is the weak acid so pH of given titrating mixture is calculated as follows,

Given,

0.150M acetic acid.

0.350M of sodium acetate

Ka of acetic acid = 1.8x10-5

Find the moles of acid and base that present in given solution.

The ICE table is,

                        Chemistry homework question answer, step 1, image 1

From the table pH of the solution is,

                            Chemistry homework question answer, step 1, image 2

x = H3O+ ion concentration in solution

Hence, pH of the solution is,

                                                          Chemistry homework question answer, step 1, image 3

Answer: the pH of given titrating mixture is 5.11.

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