The net force Facting on an objeet that moves along a straight line is given as a function of time t by F(t) = xt +r. where IN/s andr=1N. What is the change in momentum of the object from t=0s tot 3s 6 kg-ms B 10 kg s c 12 kg/s 30 kg-ms tcannot be determined without knowing the initial momentum of the object

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Chapter1: Units, Trigonometry. And Vectors
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The net force \( F \) acting on an object that moves along a straight line is given as a function of time \( t \) by \( F(t) = \kappa t + \tau \), where \( \kappa = 1 \, \text{N/s}^2 \) and \( \tau = 1 \, \text{N} \). What is the change in momentum of the object from \( t = 0 \) to \( t = 3 \, \text{s} \)?

Options:
- A) \( 6 \, \text{kg} \cdot \text{m/s} \)
- B) \( 10 \, \text{kg} \cdot \text{m/s} \)
- C) \( 12 \, \text{kg} \cdot \text{m/s} \)
- D) \( 30 \, \text{kg} \cdot \text{m/s} \)
- E) It cannot be determined without knowing the initial momentum of the object.
Transcribed Image Text:The net force \( F \) acting on an object that moves along a straight line is given as a function of time \( t \) by \( F(t) = \kappa t + \tau \), where \( \kappa = 1 \, \text{N/s}^2 \) and \( \tau = 1 \, \text{N} \). What is the change in momentum of the object from \( t = 0 \) to \( t = 3 \, \text{s} \)? Options: - A) \( 6 \, \text{kg} \cdot \text{m/s} \) - B) \( 10 \, \text{kg} \cdot \text{m/s} \) - C) \( 12 \, \text{kg} \cdot \text{m/s} \) - D) \( 30 \, \text{kg} \cdot \text{m/s} \) - E) It cannot be determined without knowing the initial momentum of the object.
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