The need arises in a laboratory for 5000cm3 of an antifreeze solution consisting of 50mol% of HCl in water. What volumes of pure HCI and pure water at 25°c must be mixed to form 5000cm3 of antifreeze, also at 25°c partial molar volume of HCl and water in 50 mol% HCl solution and pure species volume, both at 25°c are: HCI : V 1=25.8956 cm³/mol , v1=75.8963 cm³/mol Water: 2 =42.5632 cm³/mol , v2=25.2362 cm3/mol.----- V --- (b). Prove Cp-Cy = R--------

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The need arises in a laboratory for 5000cm3 of an antifreeze solution consisting
of 50mol% of HCl in water. What volumes of pure HCI and pure water at 25°c
must be mixed to form 5000cm3 of antifreeze, also at 25°c partial molar volume
of HCl and water in 50 mol% HCl solution and pure species volume, both at 25°c
are:
HCI
: V
1=25.8956 cm³/mol , v1=75.8963 cm³/mol
Water:
2 =42.5632 cm³/mol , v2=25.2362 cm3/mol.-----
V
---
(b). Prove Cp-Cy = R--------
Transcribed Image Text:The need arises in a laboratory for 5000cm3 of an antifreeze solution consisting of 50mol% of HCl in water. What volumes of pure HCI and pure water at 25°c must be mixed to form 5000cm3 of antifreeze, also at 25°c partial molar volume of HCl and water in 50 mol% HCl solution and pure species volume, both at 25°c are: HCI : V 1=25.8956 cm³/mol , v1=75.8963 cm³/mol Water: 2 =42.5632 cm³/mol , v2=25.2362 cm3/mol.----- V --- (b). Prove Cp-Cy = R--------
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