The n and I quantum numbers plus number of nodes in the following radial solution of the Schroedinger equationfor a hydrogenic atom are:3/24/23a0ZrR(r) =Zre Zr/3ay6a03aoOn=2,1 0, nodes 2On 2,1 1, nodes 2O n= 3,1 = 1, nodes 2O n = 3,1= 1, nodes 1n = 2,1= 0, odes = 3

No. of nodes= ( n-1) n is principal quantum number, and l is azimuthal quantum no.

The n and I quantum numbers plus number of nodes in the following radial solution of the Schroedinger equation for a hydrogenic atom are: AN2 (三)”(-)- 3/2 Zr 1 6ao Zr e Ze/3a R(r) = 3 3ao ao On=2,1= 0, nodes 2 On=2,1- 1, nodes 2 O n = 3,1 = 1, nodes 2 On= 3,1= 1, nodes 1 O n = 2,1 =0, nodes = 3

The n and I quantum numbers plus number of nodes in the following radial solution of the Schroedinger equation for a hydrogenic atom are: AN2 (三)”(-)- 3/2 Zr 1 6ao Zr e Ze/3a R(r) = 3 3ao ao On=2,1= 0, nodes 2 On=2,1- 1, nodes 2 O n = 3,1 = 1, nodes 2 On= 3,1= 1, nodes 1 O n = 2,1 =0, nodes = 3

Chemistry

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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

The n and I quantum numbers plus number of nodes in the following radial solution of the Schroedinger equation
for a hydrogenic atom are:
3/2
4/2
3a0
Zr
R(r) =
Zr
e Zr/3ay
6a0
3
ao
On=2,1 0, nodes 2
On 2,1 1, nodes 2
O n= 3,1 = 1, nodes 2
O n = 3,1= 1, nodes 1
n = 2,1= 0, odes = 3

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