The motion of a point on the circumference of a rolling wheel of radius 5 feet is described by the vector function r(t) = 5(12t - sin(12t))2 +5(1-cos(12t))) Find the velocity vector of the point. v(t) = 60(1- cos (12t)i + sin(12t)j) × Find the acceleration vector of the point. ä(t) = 720(sin(12t)i + cos (12t)j) Find the speed of the point. s(t) 120 sin (6t) (Write i, j, k for 2, 3, K.) X

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