The motion of a point on the circumference of a rolling wheel of radius 3 feet is described by the vector function F(t) = 3(22t – sin(22t))i + 3(1 – cos(22t)) Find the velocity vector of the point. v(t) =| (66– 66 cos ( 22t) ) i + 66 sin( 22t ) j Find the acceleration vector of the point. a(t) = Find the speed of the point. s(t) = 66y cos( 22t) + sin(22t ) ×

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