= 1 mA/V?The MOSFET in the common-source amplifier below has V = 1 V and k,(A = 0). Notice that the current source and 100 k resistor form a Norton cquivalent circuit.+ 4 V2 mA100 kvout5 M1 MQ1vsa) Determine Vps without the 100 k resistor. Use your result to calculate the current throughthe 100 k resistor. Roughly how large an crror was made by not including the 100 k resistorin the d.c. analysis?b) Draw the small-signal cquivalent circuit and determine the gain. Replacing the drainresistor with a current source has resulted in a large increase in gain!c) Determine the input resistance and the output resistance of the amplifier.

The metal oxide silicon field effect transistor (MOSFET) or metal oxide semiconductor field effect…

Answered: The MOSFET in the common-source…

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The MOSFET in the common-source amplifier below has V = 1 V and km %3D

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

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Question

= 1 mA/V?
The MOSFET in the common-source amplifier below has V = 1 V and k,
(A = 0). Notice that the current source and 100 k resistor form a Norton cquivalent circuit.
+ 4 V
2 mA
100 k
vout
5 M
1 M
Q1
vs
a) Determine Vps without the 100 k resistor. Use your result to calculate the current through
the 100 k resistor. Roughly how large an crror was made by not including the 100 k resistor
in the d.c. analysis?
b) Draw the small-signal cquivalent circuit and determine the gain. Replacing the drain
resistor with a current source has resulted in a large increase in gain!
c) Determine the input resistance and the output resistance of the amplifier.

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