The mol’s of Al2(SO4)3 that has 26 mol of S also has: 1 mol(Al2(SO4)3) ⇔ 3 mol(S) ⇔ 2 mol(Al) ⇔ 12 mol(O) ⇔ ... ... ⇔ __ mol(SO42–) ⇔ __ mol(all atoms in 1 formula unit) 26 mol(S) x ____mol(Al)/____ mol (S) = ____(Al) 26 mol(S) X ____mol(O)/___mol(S) = mol(O) 26 mol (S) x ___mol(SO42-)/___mol(S) = ___mol(SO42-) 26 mol(S) x ___mol(all atoms)/____mol(S) = ___mol(all atoms)
The mol’s of Al2(SO4)3 that has 26 mol of S also has: 1 mol(Al2(SO4)3) ⇔ 3 mol(S) ⇔ 2 mol(Al) ⇔ 12 mol(O) ⇔ ... ... ⇔ __ mol(SO42–) ⇔ __ mol(all atoms in 1 formula unit) 26 mol(S) x ____mol(Al)/____ mol (S) = ____(Al) 26 mol(S) X ____mol(O)/___mol(S) = mol(O) 26 mol (S) x ___mol(SO42-)/___mol(S) = ___mol(SO42-) 26 mol(S) x ___mol(all atoms)/____mol(S) = ___mol(all atoms)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The mol’s of Al2(SO4)3 that has 26 mol of S also has:
1 mol(Al2(SO4)3) ⇔ 3 mol(S) ⇔ 2 mol(Al) ⇔ 12 mol(O) ⇔ ...
... ⇔ __ mol(SO42–) ⇔ __ mol(all atoms in 1 formula unit)
26 mol(S) x ____mol(Al)/____ mol (S) = ____(Al)
26 mol(S) X ____mol(O)/___mol(S) = mol(O)
26 mol (S) x ___mol(SO42-)/___mol(S) = ___mol(SO42-)
26 mol(S) x ___mol(all atoms)/____mol(S) = ___mol(all atoms)
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