Consider the following made-up compound: (Z3J)2Q3 Determine the number of moles of Z in 1.75 moles of (Z3J)2Q3 Please refer to the Mini Periodic Table of Fake Elements to answer your questions 10.5 Avogadro's Number: 6.022 x 1023 O 5.25 Mini Periodic Table of Fake Elements O 1.75 D 15.00 J 19.00 Q 35.00 Z 70.00
Consider the following made-up compound: (Z3J)2Q3 Determine the number of moles of Z in 1.75 moles of (Z3J)2Q3 Please refer to the Mini Periodic Table of Fake Elements to answer your questions 10.5 Avogadro's Number: 6.022 x 1023 O 5.25 Mini Periodic Table of Fake Elements O 1.75 D 15.00 J 19.00 Q 35.00 Z 70.00
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Mini Periodic Table of Fake Elements Educational Exercise**
**Problem Statement:**
Consider the following made-up compound: \( (Z_3J)_2Q_3 \)
**Task:**
Determine the number of moles of Z in 1.75 moles of \( (Z_3J)_2Q_3 \).
**Guidance:**
Please refer to the Mini Periodic Table of Fake Elements to answer your questions.
**Mini Periodic Table of Fake Elements:**
- **D**: Atomic Weight = 15.00
- **J**: Atomic Weight = 19.00
- **Q**: Atomic Weight = 35.00
- **Z**: Atomic Weight = 70.00
**Additional Information:**
- **Avogadro's Number**: \( 6.022 \times 10^{23} \)
**Multiple Choice Answers:**
- \( \circ \) 10.5
- \( \circ \) 5.25
- \( \circ \) 1.75
**Explanation:**
The compound \( (Z_3J)_2Q_3 \) consists of:
- Three atoms of Z in each Z3 unit.
- Two Z3 units for each molecule.
- Therefore, six atoms of Z in total per molecule.
For 1.75 moles of the compound, calculate the moles of Z:
\[ \text{Moles of Z} = 1.75 \, \text{moles of} \, (Z_3J)_2Q_3 \times 6 \, \text{atoms of Z/molecule} \]
Answer the question based on these calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2e0fd676-419d-4301-a034-c95f84ed10f8%2F253f9531-64ff-4012-8ed0-6f425f5701fe%2Fgbgh7q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Mini Periodic Table of Fake Elements Educational Exercise**
**Problem Statement:**
Consider the following made-up compound: \( (Z_3J)_2Q_3 \)
**Task:**
Determine the number of moles of Z in 1.75 moles of \( (Z_3J)_2Q_3 \).
**Guidance:**
Please refer to the Mini Periodic Table of Fake Elements to answer your questions.
**Mini Periodic Table of Fake Elements:**
- **D**: Atomic Weight = 15.00
- **J**: Atomic Weight = 19.00
- **Q**: Atomic Weight = 35.00
- **Z**: Atomic Weight = 70.00
**Additional Information:**
- **Avogadro's Number**: \( 6.022 \times 10^{23} \)
**Multiple Choice Answers:**
- \( \circ \) 10.5
- \( \circ \) 5.25
- \( \circ \) 1.75
**Explanation:**
The compound \( (Z_3J)_2Q_3 \) consists of:
- Three atoms of Z in each Z3 unit.
- Two Z3 units for each molecule.
- Therefore, six atoms of Z in total per molecule.
For 1.75 moles of the compound, calculate the moles of Z:
\[ \text{Moles of Z} = 1.75 \, \text{moles of} \, (Z_3J)_2Q_3 \times 6 \, \text{atoms of Z/molecule} \]
Answer the question based on these calculations.
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