Consider the following made-up compound: (Z3J)2Q3 Determine the number of moles of Z in 1.75 moles of (Z3J)2Q3 Please refer to the Mini Periodic Table of Fake Elements to answer your questions 10.5 Avogadro's Number: 6.022 x 1023 O 5.25 Mini Periodic Table of Fake Elements O 1.75 D 15.00 J 19.00 Q 35.00 Z 70.00

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**Mini Periodic Table of Fake Elements Educational Exercise**

**Problem Statement:**

Consider the following made-up compound: \( (Z_3J)_2Q_3 \)

**Task:**

Determine the number of moles of Z in 1.75 moles of \( (Z_3J)_2Q_3 \).

**Guidance:**

Please refer to the Mini Periodic Table of Fake Elements to answer your questions.

**Mini Periodic Table of Fake Elements:**

- **D**: Atomic Weight = 15.00
- **J**: Atomic Weight = 19.00
- **Q**: Atomic Weight = 35.00
- **Z**: Atomic Weight = 70.00

**Additional Information:**

- **Avogadro's Number**: \( 6.022 \times 10^{23} \)

**Multiple Choice Answers:**

- \( \circ \) 10.5
- \( \circ \) 5.25
- \( \circ \) 1.75

**Explanation:**

The compound \( (Z_3J)_2Q_3 \) consists of:

- Three atoms of Z in each Z3 unit.
- Two Z3 units for each molecule.
- Therefore, six atoms of Z in total per molecule.

For 1.75 moles of the compound, calculate the moles of Z:

\[ \text{Moles of Z} = 1.75 \, \text{moles of} \, (Z_3J)_2Q_3 \times 6 \, \text{atoms of Z/molecule} \]

Answer the question based on these calculations.
Transcribed Image Text:**Mini Periodic Table of Fake Elements Educational Exercise** **Problem Statement:** Consider the following made-up compound: \( (Z_3J)_2Q_3 \) **Task:** Determine the number of moles of Z in 1.75 moles of \( (Z_3J)_2Q_3 \). **Guidance:** Please refer to the Mini Periodic Table of Fake Elements to answer your questions. **Mini Periodic Table of Fake Elements:** - **D**: Atomic Weight = 15.00 - **J**: Atomic Weight = 19.00 - **Q**: Atomic Weight = 35.00 - **Z**: Atomic Weight = 70.00 **Additional Information:** - **Avogadro's Number**: \( 6.022 \times 10^{23} \) **Multiple Choice Answers:** - \( \circ \) 10.5 - \( \circ \) 5.25 - \( \circ \) 1.75 **Explanation:** The compound \( (Z_3J)_2Q_3 \) consists of: - Three atoms of Z in each Z3 unit. - Two Z3 units for each molecule. - Therefore, six atoms of Z in total per molecule. For 1.75 moles of the compound, calculate the moles of Z: \[ \text{Moles of Z} = 1.75 \, \text{moles of} \, (Z_3J)_2Q_3 \times 6 \, \text{atoms of Z/molecule} \] Answer the question based on these calculations.
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