The Mole Concept Sulfur compounds are converted to H2SO, while NO, compounds are converted to HNO3, and NH3 reacts with these acids to form ammonium salts. Since acidifying deposition involves different substances, one process that naturally occurs is nitrification via bacterial conversion according to: (MN = 14.01 g/mol. Mo-16.00 g/mol, MH = 1.008 g/mol, Ms - 32.07 g/mol) %3D NH + 20, → NO, + H,0+ 2H A. If 10.15 g of NH,* was found in the soil, how many ions of NH." was present initially? B. If 256 g of H20 was produced after nitrification, how many moles of H were co-produced? C. How many grams of O are found in 7.40 x 1024 atoms of NO, was produced? D. How many atoms of O are found in 9.30 mmol of 02?

The Mole Concept Sulfur compounds are converted to H2SO, while NO, compounds are converted to HNO3, and NH3 reacts with these acids to form ammonium salts. Since acidifying deposition involves different substances, one process that naturally occurs is nitrification via bacterial conversion according to: (MN = 14.01 g/mol. Mo-16.00 g/mol, MH = 1.008 g/mol, Ms - 32.07 g/mol) %3D NH + 20, → NO, + H,0+ 2H A. If 10.15 g of NH,* was found in the soil, how many ions of NH." was present initially? B. If 256 g of H20 was produced after nitrification, how many moles of H were co-produced? C. How many grams of O are found in 7.40 x 1024 atoms of NO, was produced? D. How many atoms of O are found in 9.30 mmol of 02?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A sample of soda ash (impure Na2CO3) is titrated with 0.5000 N H2SO4. If the sample weighs 1.1000 g requires 35.00 mL of the acid for complete neutralization, what is the %Na2CO3 in the ash assuming no other active component is present? (; Na 22.99, C 12.01, O 16.00, H 1.008, S 32.07)
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