The molar mass of a polymer can be determined from the osmotic pressure of a solution. If the osmotic pressure of a solution containing 5.00 g of polymer in 1.00 L of benzene is 42 mmHg (T = 25.0 "C) what is the molar mass? 8.6x10 g/mol O 3.1x10 g/mol 1.9×104 gimol O 22x10 gimol

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### Determining the Molar Mass of a Polymer Using Osmotic Pressure

Use the References to access important values if needed for this question.

The molar mass of a polymer can be determined from the osmotic pressure of a solution. If the osmotic pressure of a solution containing 5.00 g of polymer in 1.00 L of benzene is 42 mmHg (T = 25.0 °C), what is the molar mass?

- A) \(8.6 \times 10^4\) g/mol
- B) \(3.1 \times 10^3\) g/mol
- C) \(1.9 \times 10^4\) g/mol
- D) \(2.2 \times 10^4\) g/mol

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Transcribed Image Text:Certainly! Here is the transcription for educational purposes: --- ### Determining the Molar Mass of a Polymer Using Osmotic Pressure Use the References to access important values if needed for this question. The molar mass of a polymer can be determined from the osmotic pressure of a solution. If the osmotic pressure of a solution containing 5.00 g of polymer in 1.00 L of benzene is 42 mmHg (T = 25.0 °C), what is the molar mass? - A) \(8.6 \times 10^4\) g/mol - B) \(3.1 \times 10^3\) g/mol - C) \(1.9 \times 10^4\) g/mol - D) \(2.2 \times 10^4\) g/mol --- Note: A small video thumbnail or image from a different screen is visible in the corner, which seems unrelated to the text content.
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