The mine skip is being hauled to the surface over the curved track by the cable wound around the 36-in. drum, which turns at theconstant clockwise speed of 114 rev/min. The shape of the track is designed so that y = x²/49, where x and y are in feet. Calculate themagnitude of the total acceleration of the skip as it reaches a level of 1.8 ft below the top. Neglect the dimensions of the skip comparedwith those of the path. Recall that the radius of curvature is given byAnswer: a = ip=1+dy 23/2dxd²ydx²36"ft/sec²

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