=J (e) (b) Fe= () 6. A pendulum that consists of a ball (m = 1.50 kg) attached to a light cord rotates in a circular path of radius r = 0.800 m at constant speed v, as shown in Figure. Here the angle 0 = 65°, and we ignore air friction and assume the mass of the light cord is negligible. (a) Calculate the tension T in the cord. = L. (b) Calculate the centripetal force acting on the ball. = 'd (c) Calculate the velocity v of this uniform circular motion. Answers:

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Chapter1: Units, Trigonometry. And Vectors
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=J (e)
(b) Fe=
()
6. A pendulum that consists of a ball (m = 1.50 kg) attached to a light cord rotates in a circular path of
radius r = 0.800 m at constant speed v, as shown in Figure. Here the angle 0 = 65°, and we ignore air
friction and assume the mass of the light cord is negligible.
(a) Calculate the tension T in the cord.
= L.
(b) Calculate the centripetal force acting on the ball.
= 'd
(c) Calculate the velocity v of this uniform circular motion.
Answers:
Transcribed Image Text:=J (e) (b) Fe= () 6. A pendulum that consists of a ball (m = 1.50 kg) attached to a light cord rotates in a circular path of radius r = 0.800 m at constant speed v, as shown in Figure. Here the angle 0 = 65°, and we ignore air friction and assume the mass of the light cord is negligible. (a) Calculate the tension T in the cord. = L. (b) Calculate the centripetal force acting on the ball. = 'd (c) Calculate the velocity v of this uniform circular motion. Answers:
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