The melting point of water at the pressure of interest is 0.00 ∘C, and the enthalpy of fusion is 6.010 kJ⋅mol−1. The boiling point is 100. ∘C, and the enthalpy of vaporization is 40.65 kJ⋅mol−1. Calculate ΔS for the transformation of the same amount of water which is 1.85 mol.

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Chapter1: Chemical Foundations
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The melting point of water at the pressure of interest is 0.00 ∘C, and the enthalpy of fusion is 6.010 kJ⋅mol−1. The boiling point is 100. ∘C, and the enthalpy of vaporization is 40.65 kJ⋅mol−1. Calculate ΔS for the transformation of the same amount of water which is 1.85 mol.

Calculate AS if 1.85 mol of liquid water is heated from 0.00 °C to 23.4 ° C under constant pressure if Cp.m
= 75.3 J. K-1. mol1.
Express your answer with the appropriate units.
11.5 J.K-1
Submit
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Correct
Part B
The melting point of water at the pressure of interest is 0.00 °C, and the enthalpy of fusion is 6.010 kJ · mol . The boiling point is 100. °C, and the enthalpy of
vaporization is 40.65 kJ · mol. Calculate AS for the transformation of the same amount of water
H2O (s, 0.00 °C) → H2O (g, 100. °C)
Express your answer with the appropriate units.
HẢ
?
J
174.478
K
Submit
Previous Answers Request Answer
Incorrect; Try Again; 4 attempts remaining
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Transcribed Image Text:Calculate AS if 1.85 mol of liquid water is heated from 0.00 °C to 23.4 ° C under constant pressure if Cp.m = 75.3 J. K-1. mol1. Express your answer with the appropriate units. 11.5 J.K-1 Submit Previous Answers Correct Part B The melting point of water at the pressure of interest is 0.00 °C, and the enthalpy of fusion is 6.010 kJ · mol . The boiling point is 100. °C, and the enthalpy of vaporization is 40.65 kJ · mol. Calculate AS for the transformation of the same amount of water H2O (s, 0.00 °C) → H2O (g, 100. °C) Express your answer with the appropriate units. HẢ ? J 174.478 K Submit Previous Answers Request Answer Incorrect; Try Again; 4 attempts remaining Pearson
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