Please answer A through E. The mean age of a random sample of 25 people who were playing the slot machines is 48.7 years, and the standard deviation is 6.8years. The mean age of a random sample of 35 people who were playing roulette is 55.3 with a standard deviation of 3.2 years. Canit be concluded at a =0.10 that the mean age of those playing the slot machines is less than those playing roulette? Assumepopulations are normaly distributed.a. Determine whether this is a right tailed test, left tailed test or two tailed test.(If the answer isRight tailed, type "right", if the answer is Left tailed type "left", if the answer is Two tailed type "two")b. Compute the value of the test statistic (Provide the answer with 3 decimal places).c. How many degrees of freedom are there?d. What is the critical value/ P-value? (Provide the answer with 3 decimal places)e. Do you reject the null hypothesis? (If the answer is yes, type "y", if the answer is no type "n")

Name: Please answer A through E. The mean age of a random sample of 25 peopl
Uploaded: 2024-03-20T06:38:44.000Z
Channel: Bartleby
Description: Please answer A through E. The mean age of a random sample of 25 people who were playing the slot machines is 48.7 years, and the standard deviation is 6.8years. The mean age of a random sample of 35 people who were playing roulette is 55.3 with a st

Given Information: Sample size of people playing slot machines (n1) = 25 Mean age of people playing the slot machines (x1) = 48.7 years Standard Deviation of people playing the slot machines (s1) = 6.8 years Sample size of people playing roulette (n2) = 35 Mean age of people playing the slot machines (x2) = 55.3 years Standard Deviation of people playing the slot machines (s2) = 3.2 years a) This is a left tailed test b) The test statistic can be computed as follows: t= x1-x2s12n1+s22n2=48.7-55.36.8225+3.2235=-4.509c) The degrees of freedom (df) = n1 + n2 -2 = 25 +35 -2 = 58 d) By referring the t-distribution table, the p-value at t = -4.509 and df = 58 is 0.00032 e) Since the p-value is less than the alpha value, the null hypothesis is rejected. So answer is yes.