The mass of a hydrogen atom (11H)(11H) is 1.007825 amu; that of a tritium atom (31H)(13H) is 3.01605 amu; and that of an α particle is 4.00150 amu. How much energy in kilojoules per mole of 42He24He produced is released by the following fusion reaction: 11H+31H⟶42He.
The mass of a hydrogen atom (11H)(11H) is 1.007825 amu; that of a tritium atom (31H)(13H) is 3.01605 amu; and that of an α particle is 4.00150 amu. How much energy in kilojoules per mole of 42He24He produced is released by the following fusion reaction: 11H+31H⟶42He.
Fusion reaction:
1H1 + 3 H1 -----------> 2He4
Mass of 1H = 1.007825 amu
Mass of H3 = 3.01605 amu
Hence on fusion expected mass of 4α is 1.007825+3.01605 = 4.023875 amu
But actual (Observed) mass of 4α is 4.00150 amu.
The difference between expected mass and observed mass is called mass defect (Δm) which is converted into the energy.
Let us calculate the mass defect (Δm).
Δm = Expected Mass – Observed Mass
Δm = 4.023875 – 4. 00150
Δm = 0.022375 amu
Δm = 0.022375 x (1.66 x 10-27) Kg ……… (Since, 1amu = 1.66 x 10-27 Kg.)
Δm = 3.71 x 10-29 Kg
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