The magnitude of the net force exerted in the x direction on a 3.80-kg particle varies in time as shown in the figure below. F (N) 4 3 2 1 t (s) 1 3 4

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The image describes a physics problem involving a 3.80-kg particle subjected to a varying force along the x-direction over a time interval of 5.00 seconds.

**Graph Description:**
- The graph shows the force \( F \) (in Newtons) plotted against time \( t \) (in seconds).
- The force increases linearly from 0 N at \( t = 0 \) s to 4 N at \( t = 2 \) s.
- The force remains constant at 4 N between \( t = 2 \) s and \( t = 3 \) s.
- The force decreases linearly back to 0 N from \( t = 3 \) s to \( t = 5 \) s.

**Questions and Incorrect Answers:**

(a) Find the impulse of the force over the 5.00-s time interval.

\[ \vec{I} = \boxed{12} \, \text{N} \cdot \text{s} \, \text{(Incorrect)} \]

(b) Find the final velocity the particle attains if it is originally at rest.

\[ \vec{v}_f = \boxed{3.16} \, \text{m/s} \, \text{(Incorrect)} \]

(c) Find its final velocity if its original velocity is \(-3.00 \, \hat{\imath}\) m/s.

\[ \vec{v}_f = \boxed{0.16} \, \text{m/s} \, \text{(Incorrect)} \]

(d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s.

\[ \vec{F}_{\text{avg}} = \boxed{2.4} \, \text{N} \, \text{(Incorrect)} \]
Transcribed Image Text:The image describes a physics problem involving a 3.80-kg particle subjected to a varying force along the x-direction over a time interval of 5.00 seconds. **Graph Description:** - The graph shows the force \( F \) (in Newtons) plotted against time \( t \) (in seconds). - The force increases linearly from 0 N at \( t = 0 \) s to 4 N at \( t = 2 \) s. - The force remains constant at 4 N between \( t = 2 \) s and \( t = 3 \) s. - The force decreases linearly back to 0 N from \( t = 3 \) s to \( t = 5 \) s. **Questions and Incorrect Answers:** (a) Find the impulse of the force over the 5.00-s time interval. \[ \vec{I} = \boxed{12} \, \text{N} \cdot \text{s} \, \text{(Incorrect)} \] (b) Find the final velocity the particle attains if it is originally at rest. \[ \vec{v}_f = \boxed{3.16} \, \text{m/s} \, \text{(Incorrect)} \] (c) Find its final velocity if its original velocity is \(-3.00 \, \hat{\imath}\) m/s. \[ \vec{v}_f = \boxed{0.16} \, \text{m/s} \, \text{(Incorrect)} \] (d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s. \[ \vec{F}_{\text{avg}} = \boxed{2.4} \, \text{N} \, \text{(Incorrect)} \]
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