**Problem Statement:**As a protest against the umpire's calls, a baseball pitcher throws a ball straight up into the air at a speed of 21.5 m/s. In the process, he moves his hand through a distance of 1.45 m. If the ball has a mass of 0.150 kg, find the force he exerts on the ball to give it this upward speed.**Variables Given:**- Initial speed (v) = 21.5 m/s- Distance (d) = 1.45 m- Mass (m) = 0.150 kg**Objective:**Calculate the force exerted on the ball.**Calculation:**To solve this problem, you would typically use the work-energy principle which relates the work done on the ball to its change in kinetic energy. The work done (W) by the force (F) is given by: \[ W = F \cdot d \]The change in kinetic energy (ΔKE) is given by:\[ ΔKE = \frac{1}{2} m v^2 - \frac{1}{2} m \cdot 0^2 = \frac{1}{2} m v^2 \]Since the work done is equal to the change in kinetic energy:\[ F \cdot d = \frac{1}{2} m v^2 \]Solving for F (Force):\[ F = \frac{\frac{1}{2} m v^2}{d} \]**Graphs and Diagrams:**No graphs or diagrams are present in the image. This explanation would typically accompany a diagram showing a pitcher throwing the ball, with forces labeled and an indication of the initial velocity and distance moved by the hand.

Name: **Problem Statement:**As a protest against the umpire's calls, a base
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: **Problem Statement:**As a protest against the umpire's calls, a baseball pitcher throws a ball straight up into the air at a speed of 21.5 m/s. In the process, he moves his hand through a distance of 1.45 m. If the ball has a mass of 0.150 kg, find