The magnitude of the net force exerted in the x direction on a 2.15-kg particle varies in time as shown in the figure below. F (N) 4 3 n 2 1 1 34 t (s) (a) Find the impulse of the force over the 5.00-s time interval. Ī N.S (b) Find the final velocity the particle attains if it is originally at rest. m/s (c) Find its final velocity if its original velocity is -3.50 î m/s. 7₁- m/s (d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s. F N avg

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Chapter1: Units, Trigonometry. And Vectors
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The magnitude of the net force exerted in the x direction on a 2.15-kg particle varies in time as shown in the figure below.
F (N)
4
3
2
1
t(s)
(a) Find the impulse of the force over the 5.00-s time interval.
Ỉ =
N.S
1 2 3 4 5
(b) Find the final velocity the particle attains if it is originally at rest.
✔f
m/s
(c) Find its final velocity if its original velocity is -3.50 î m/s.
√ ₁ =
m/s
avg
(d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s.
F
N
=
Transcribed Image Text:The magnitude of the net force exerted in the x direction on a 2.15-kg particle varies in time as shown in the figure below. F (N) 4 3 2 1 t(s) (a) Find the impulse of the force over the 5.00-s time interval. Ỉ = N.S 1 2 3 4 5 (b) Find the final velocity the particle attains if it is originally at rest. ✔f m/s (c) Find its final velocity if its original velocity is -3.50 î m/s. √ ₁ = m/s avg (d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s. F N =
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