The magnetic field strength at the north pole of a 2.0-cm-diameter, 8-cm-long permanent magnet is 0.10 T. To produce the same field with a solenoid of the same size, carrying a current of 1.8 A, how man need? Express your answer to two significant figures.
The magnetic field strength at the north pole of a 2.0-cm-diameter, 8-cm-long permanent magnet is 0.10 T. To produce the same field with a solenoid of the same size, carrying a current of 1.8 A, how man need? Express your answer to two significant figures.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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
Transcribed Image Text:### Part A: Solenoid Magnetic Field Calculation
#### Problem Statement:
The magnetic field strength at the north pole of a 2.0-cm diameter, 8-cm long permanent magnet is 0.10 T.
#### Question:
To produce the same magnetic field with a solenoid of the same size carrying a current of 1.8 A, how many turns of wire would you need?
**Express your answer to two significant figures.**
#### Input Field:
- **Formula Input:** \( N = \) (turns)
**Graphical Buttons:** Supported mathematical symbols and operations to input formulas.
#### Submit Options:
- **Submit**
- **Previous Answers**
- **Request Answer**
This setup aids students in calculating the required number of turns in the solenoid to match the magnetic field strength of a given permanent magnet.
### Explanation of Graphs and Diagrams:
There are no graphs or diagrams associated with this problem; it relies entirely on textual and mathematical input fields for students to calculate the required number of turns.
#### Notes:
- **N** represents the number of turns of wire in the solenoid.
- The provided magnetic field strength (0.10 T), diameter (2.0 cm), and length (8 cm) of the magnet are crucial parameters.
- The current running through the solenoid is given as 1.8 A.
Ensure to utilize correct magnetic field equations relevant to solenoids to solve this problem accurately.
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