The magnetic field strength at the north pole of a 2.0-cm-diameter, 8-cm-long permanent magnet is 0.10 T. Part A To produce the same field with a solenoid of the same size, carrying a current of 1.8 A, how many turns of wire would you need? Express your answer to two significant figures. 15. ΑΣΦ ? N = Submit Previous Answers Request Answer turns

Inquiry into Physics
8th Edition
ISBN:9781337515863
Author:Ostdiek
Publisher:Ostdiek
Chapter8: Electromagnetism And Em Waves
Section: Chapter Questions
Problem 4C: The right-hand rule is a way to determine the direction of the magnetic field produced by moving...
icon
Related questions
Question
### Magnetic Field of a Permanent Magnet and Solenoid

#### Context
This content relates to understanding the magnetic field strength produced by a permanent magnet and comparing it to that produced by a solenoid.

#### Problem Statement
The magnetic field strength at the north pole of a permanent magnet, which is 2.0 cm in diameter and 8 cm in length, is 0.10 T.

#### Objective
To produce the same magnetic field strength with a solenoid of the same size, carrying a current of 1.8 A, how many turns of wire would be needed?

#### Instructions
- **Express your answer to two significant figures.**

##### Input Field:
- \( N = \) [__________] turns

##### Actions Available:
- **Submit**
- **Previous Answers**
- **Request Answer**

The user is expected to calculate the number of turns (\( N \)) of the wire required for the solenoid to produce a magnetic field of 0.10 T given a current of 1.8 A.

### Background Information
- **Permanent Magnet**: A magnet that maintains its magnetic properties even in the absence of an external magnetic field.
- **Solenoid**: A coil of wire designed to generate a magnetic field when an electric current passes through it.
- **Magnetic Field (B)**: The magnetic influence produced by electric currents and magnetic materials.

#### Input Parameters:
- Diameter of magnet: 2.0 cm
- Length of magnet: 8 cm
- Magnetic field strength: 0.10 T (tesla)
- Solenoid current: 1.8 A (amperes)

### Formula (For self-calculation)
The magnetic field \( B \) inside a solenoid is given by:

\[ B = \mu_0 \frac{N}{L} I \]

Where:
- \( B \) is the magnetic field strength (tesla, T)
- \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, \text{T·m/A} \))
- \( N \) is the number of turns of the coil
- \( L \) is the length of the solenoid (meters, m)
- \( I \) is the current through the solenoid (amperes, A)

#### Application
Based on these parameters, someone can calculate the required number of turns \( N \)
Transcribed Image Text:### Magnetic Field of a Permanent Magnet and Solenoid #### Context This content relates to understanding the magnetic field strength produced by a permanent magnet and comparing it to that produced by a solenoid. #### Problem Statement The magnetic field strength at the north pole of a permanent magnet, which is 2.0 cm in diameter and 8 cm in length, is 0.10 T. #### Objective To produce the same magnetic field strength with a solenoid of the same size, carrying a current of 1.8 A, how many turns of wire would be needed? #### Instructions - **Express your answer to two significant figures.** ##### Input Field: - \( N = \) [__________] turns ##### Actions Available: - **Submit** - **Previous Answers** - **Request Answer** The user is expected to calculate the number of turns (\( N \)) of the wire required for the solenoid to produce a magnetic field of 0.10 T given a current of 1.8 A. ### Background Information - **Permanent Magnet**: A magnet that maintains its magnetic properties even in the absence of an external magnetic field. - **Solenoid**: A coil of wire designed to generate a magnetic field when an electric current passes through it. - **Magnetic Field (B)**: The magnetic influence produced by electric currents and magnetic materials. #### Input Parameters: - Diameter of magnet: 2.0 cm - Length of magnet: 8 cm - Magnetic field strength: 0.10 T (tesla) - Solenoid current: 1.8 A (amperes) ### Formula (For self-calculation) The magnetic field \( B \) inside a solenoid is given by: \[ B = \mu_0 \frac{N}{L} I \] Where: - \( B \) is the magnetic field strength (tesla, T) - \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, \text{T·m/A} \)) - \( N \) is the number of turns of the coil - \( L \) is the length of the solenoid (meters, m) - \( I \) is the current through the solenoid (amperes, A) #### Application Based on these parameters, someone can calculate the required number of turns \( N \)
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Magnetic field
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Inquiry into Physics
Inquiry into Physics
Physics
ISBN:
9781337515863
Author:
Ostdiek
Publisher:
Cengage
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers with Modern …
Physics for Scientists and Engineers with Modern …
Physics
ISBN:
9781337553292
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning