The lower bound of the confidence interval is calculated using the expression x-a/2 √n -. Find this lower bound, rounding the result to two decimal places. lower bound = x-ta/2 = 253.45 1.998 = S upper bound = x+ta/2 √√n 75.50 S The upper bound of the confidence interval is calculated using the expression x + ta/2 √ to two decimal places. = 253.45 + 1.998 √64 75.50 √64 Find this upper bound, rounding the result
The lower bound of the confidence interval is calculated using the expression x-a/2 √n -. Find this lower bound, rounding the result to two decimal places. lower bound = x-ta/2 = 253.45 1.998 = S upper bound = x+ta/2 √√n 75.50 S The upper bound of the confidence interval is calculated using the expression x + ta/2 √ to two decimal places. = 253.45 + 1.998 √64 75.50 √64 Find this upper bound, rounding the result
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The sample mean was given to be x = $253.45 spent per day and the sample standard deviation was given to be s = $75.50. The
value of ta/2 was determined to be 1.998. All the values are now known to construct the confidence interval.
S
The lower bound of the confidence interval is calculated using the expression x-ta/2 √n Find this lower bound, rounding the result
to two decimal places.
lower bound =
x-ta/2
= 253.45 1.998
Ei
S
upper bound = x + ta/2 √n
The upper bound of the confidence interval is calculated using the expression x +
ta/2
to two decimal places.
75.50
= 253.45 + 1.998
√64
75.50
√64
S
√n
Find this upper bound, rounding the result
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Ę
Transcribed Image Text:upper bound = x + ta/2
412 ( √₁ )
=
253.45 +1.998
75.50
√64
Therefore, the 95% confidence interval for the population mean cost spent per day for a family of four vacationing in Niagara Falls is
from a lower bound of $
to an upper bound of $
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