The lower bound of the confidence interval is calculated using the expression x-a/2 √n -. Find this lower bound, rounding the result to two decimal places. lower bound = x-ta/2 = 253.45 1.998 = S upper bound = x+ta/2 √√n 75.50 S The upper bound of the confidence interval is calculated using the expression x + ta/2 √ to two decimal places. = 253.45 + 1.998 √64 75.50 √64 Find this upper bound, rounding the result

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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The sample mean was given to be x = $253.45 spent per day and the sample standard deviation was given to be s = $75.50. The
value of ta/2 was determined to be 1.998. All the values are now known to construct the confidence interval.
S
The lower bound of the confidence interval is calculated using the expression x-ta/2 √n Find this lower bound, rounding the result
to two decimal places.
lower bound =
x-ta/2
= 253.45 1.998
Ei
S
upper bound = x + ta/2 √n
The upper bound of the confidence interval is calculated using the expression x +
ta/2
to two decimal places.
75.50
= 253.45 + 1.998
√64
75.50
√64
S
√n
Find this upper bound, rounding the result
74°F Sunny
4:18 PM
4/17/2023
Ę
Transcribed Image Text:The sample mean was given to be x = $253.45 spent per day and the sample standard deviation was given to be s = $75.50. The value of ta/2 was determined to be 1.998. All the values are now known to construct the confidence interval. S The lower bound of the confidence interval is calculated using the expression x-ta/2 √n Find this lower bound, rounding the result to two decimal places. lower bound = x-ta/2 = 253.45 1.998 Ei S upper bound = x + ta/2 √n The upper bound of the confidence interval is calculated using the expression x + ta/2 to two decimal places. 75.50 = 253.45 + 1.998 √64 75.50 √64 S √n Find this upper bound, rounding the result 74°F Sunny 4:18 PM 4/17/2023 Ę
upper bound = x + ta/2
412 ( √₁ )
=
253.45 +1.998
75.50
√64
Therefore, the 95% confidence interval for the population mean cost spent per day for a family of four vacationing in Niagara Falls is
from a lower bound of $
to an upper bound of $
Transcribed Image Text:upper bound = x + ta/2 412 ( √₁ ) = 253.45 +1.998 75.50 √64 Therefore, the 95% confidence interval for the population mean cost spent per day for a family of four vacationing in Niagara Falls is from a lower bound of $ to an upper bound of $
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