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All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2= 1.960, o = 150, and n = 100. Find the lower bound of the confidence interval, rounding the result to the nearest integer. -zard (vn) x-E=x-Za/2 =832 1.960 Find the upper bound of the confidence interval, rounding the result to the nearest integer. -2012 (√) X+E=X+Za/2 √n of 150 ✓ 100 = 832 + 1.960 150 100 Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound to an upper bound of

All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2= 1.960, o = 150, and n = 100. Find the lower bound of the confidence interval, rounding the result to the nearest integer. -zard (vn) x-E=x-Za/2 =832 1.960 Find the upper bound of the confidence interval, rounding the result to the nearest integer. -2012 (√) X+E=X+Za/2 √n of 150 ✓ 100 = 832 + 1.960 150 100 Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound to an upper bound of

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2 = 1.960, o = 150, and n = 100. Find the lower bound of the confidence interval, rounding the result to the nearest integer. 0 - X-² a1/2 ( √ ) = 832 1.960 x-E = x-Za/2 Find the upper bound of the confidence interval, rounding the result to the nearest integer. *+-+²√) X+ E = x + 2a/2 √n 150 V100 = 832 + 1.960 of 150 √100 Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound to an upper bound of
Transcribed Image Text:All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2 = 1.960, o = 150, and n = 100. Find the lower bound of the confidence interval, rounding the result to the nearest integer. 0 - X-² a1/2 ( √ ) = 832 1.960 x-E = x-Za/2 Find the upper bound of the confidence interval, rounding the result to the nearest integer. *+-+²√) X+ E = x + 2a/2 √n 150 V100 = 832 + 1.960 of 150 √100 Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound to an upper bound of
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