Express the confidence interval (392.7, 485.7) in the form of + ME. 元士ME = 土

Express the confidence interval (45.3%,59.3%)(45.3%,59.3%) in the form of ˆp±MEp^±ME.% ± %

Do Construct a confidence interval on a slope?

You want to get a 95% confidence interval for the difference between the percentage of females with red hair compared to males with red hair. You sample 88 females and find 20 of them have red hair. You sample 79 males and find 36 have red hair. < p1−p2p1-p2 <

Express the confidence interval (595.3, 720.3) in the form of ME. I+ME= Submit Question 41⁰ H a I MATARAY hp

help

In a random sample of 250 high school students, it was found that 85.2% (213) of them later graduated. The 95% confidence interval is (-0.065,0.065) and the 98% confidence interval is (-0.077,0.077) for the true proportion of all high school students who graduate. Compare the two proportions.

Suppose that the confidence interval for the difference in the average brain wave activity is : (-10, 16). What conclusion can be made? The average brain wave activity is substantially longer for college students who drink .5 liter of red wine before bedtime, as compared to students who do not drink alcohol before bedtime. The average brain wave activity is similar when comparing college students who drink .5 liter of red wine before bedtime and college students who drink no alcohol before bedtime. The average brain wave activity is substantially shorter for college students who drink .5 liter of red wine before bedtime, as compared to students who do not drink alcohol before bedtime.

View History Bookmarks Profiles < nts 365 Library ccd.edu/courses/193580/quizzes/1502165/take ect Tool 68 ! 1 Q (23 unread) A @ 2 W X S Book Service X s. e. #3 Wildlife biologists inspect 150 deer taken by hunters and find 30 of them carrying Lyme disease ticks. Formulas: For 94% confidence level z* =1.88, p(1-p) E = 2* V n 20 F3 Tab Window Help a) The point estimate is p one decimal place. b) The standard error of the sample proportion is · (p) = Write your answer to four decimal places. E D 54 $ Student - no X c) The margin of error with confidence level of 94% is E= Write your answer to four decimal places. d) We are 94% confident that the true population proportion of deer that carry Lyme disease ticks is - O R F4 F P Parchment E X % 5 FS - T A 6 F6 Y H & 7 F7 Courses U * 8 J ► 11 F8 Round to I X ( 9 K F9 O -0 1 0 L Home | Stati X P D))83% - ; 1 F11 + 4) F12 1 = { 1 Rgu S #1 .

Studies have shown that people who suffer sudden cardiac arrest have a better chance of survival if a defibrillator shock is administered very soon after cardiac arrest. How is survival rate related to the time between when cardiac arrest occurs and when the defibrillator shock is delivered? = survival rate (percent) and x = mean call-to-shock time (minutes) for a cardiac rehabilitation center (in which cardiac arrests occurred while victims were hospitalized The accompanying data give y and so the call-to-shock time tended to be short) and for four communities of different sizes. Mean call-to-shock time, x 2 6. 7 9. 12 Survival rate, y 91 46 32 4