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the load of 6 kN/m has been changed to 11 kN/m, • the central length of 2 m has been changed to 4 m o this means the load is applied over the beam from 1 m to the right of point 'A' TO point 'C'. Measured from point 'A', where is the location of the resultant applied to the beam? 0m 0.5 m O 1m O 1.5 m 2 m 2.5 m 2.86 m 3 m 3.5 m 4 m 4.5 m 5 m 5.5 m 6 m O O O O O OO

the load of 6 kN/m has been changed to 11 kN/m, • the central length of 2 m has been changed to 4 m o this means the load is applied over the beam from 1 m to the right of point 'A' TO point 'C'. Measured from point 'A', where is the location of the resultant applied to the beam? 0m 0.5 m O 1m O 1.5 m 2 m 2.5 m 2.86 m 3 m 3.5 m 4 m 4.5 m 5 m 5.5 m 6 m O O O O O OO

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Consider the system shown in FIGURE P3-44 of the textbook. The designer has made several changes to the system. These changes are: - The load of 6 kN/m has been changed to 11 kN/m. - The central length of 2 m has been changed to 4 m. - This means the load is applied over the beam from 1 m to the right of point 'A' TO point 'C'. Measured from point ‘A’, where is the location of the resultant applied to the beam? - ○ 0 m - ○ 0.5 m - ○ 1 m - ○ 1.5 m - ○ 2 m - ○ 2.5 m - ○ 2.86 m - ○ 3 m - ○ 3.5 m - ○ 4 m - ○ 4.5 m - ○ 5 m - ○ 5.5 m - ○ 6 m
Transcribed Image Text:Consider the system shown in FIGURE P3-44 of the textbook. The designer has made several changes to the system. These changes are: - The load of 6 kN/m has been changed to 11 kN/m. - The central length of 2 m has been changed to 4 m. - This means the load is applied over the beam from 1 m to the right of point 'A' TO point 'C'. Measured from point ‘A’, where is the location of the resultant applied to the beam? - ○ 0 m - ○ 0.5 m - ○ 1 m - ○ 1.5 m - ○ 2 m - ○ 2.5 m - ○ 2.86 m - ○ 3 m - ○ 3.5 m - ○ 4 m - ○ 4.5 m - ○ 5 m - ○ 5.5 m - ○ 6 m
### Figure P3-44: Beam Diagram This figure represents a beam supported at two points, A and B, and subjected to a uniform distributed load (UDL). - **Supports:** - **A**: Fixed support - **B**: Roller support located 2 meters from support A - **Beam Lengths:** - Section AB: 2 meters - Section BC: 1 meter - **Loading:** - A uniform distributed load of 6 kN/m is applied across section BC (3 meters in total). - **Elements:** - The beam is horizontal, with arrows indicating the distribution of the load. - The load is consistent across the entire span of the beam. - Support A is indicated with a fixed support representation, providing both vertical and horizontal restraint. - Support B allows for vertical movement but restricts horizontal movement. This diagram is typically used to analyze the reactions at the supports and the internal forces within the beam (shear forces and bending moments) due to the applied load.
Transcribed Image Text:### Figure P3-44: Beam Diagram This figure represents a beam supported at two points, A and B, and subjected to a uniform distributed load (UDL). - **Supports:** - **A**: Fixed support - **B**: Roller support located 2 meters from support A - **Beam Lengths:** - Section AB: 2 meters - Section BC: 1 meter - **Loading:** - A uniform distributed load of 6 kN/m is applied across section BC (3 meters in total). - **Elements:** - The beam is horizontal, with arrows indicating the distribution of the load. - The load is consistent across the entire span of the beam. - Support A is indicated with a fixed support representation, providing both vertical and horizontal restraint. - Support B allows for vertical movement but restricts horizontal movement. This diagram is typically used to analyze the reactions at the supports and the internal forces within the beam (shear forces and bending moments) due to the applied load.
Expert Solution
Step 1

Given:

w=11 kN/ml=6 m

Solution:

 

let The resultant is acting at x distance from point A.

The magnitude of the resultant force is equal to the total load acting on the beam.

The total load is the rate of loading w in kN/m at 5 m length as :

R=w(5)=11×5 =55 kN

 

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