The lifetime of a certain brand of battery is known to have a standard deviation of 11.5 hours. Suppose that a random sample of 70 such batteries has a mean lifetime of 36.8 hours. Based on this sample, find a 99% confidence interval for the true mean lifetime of all batteries of this brand. Then give its lower limit and upper limit. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.) Lower limit:I Upper limit:

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A: It is given that the mean is 103.4 and standard deviation is 21.5.

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A: Given Information:  Mean (x)  = 96.9  Standard Deviation (s) = 23.6

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A: Given: mean=μ=95.1 standard deviation=σ=21.6

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A: Confidence interval  is a type of estimate computed from the statistics of the observed data. This…

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A: Given The tota number of men with CVD =244The tota number of women with CVD =135The tota number of…

Q: Assume that adults have IQ scores that are normally distributed with a mean of 95.1 and a standard…

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Q: Find a 90% confidence interval for the population mean age of the Smurfs if a sample of 52 smurfs…

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A: given data  n = 80 x¯ = 67σ = 1299% ci for μ = ?

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A: Let '' be the random variable representing IQ scores.According to the given information,

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Q: Assume that adults have IQ scores that are normally distributed with a mean of 100.3 and a standard…

A: From the provided information, Mean (µ) = 100.3 Standard deviation (σ) = 16.7 X~N (100.3, 16.7)

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A: Let X denote the IQ scores of adults. Given that X follows N(mean = 103.6, SD = 22.7), then Z = (X -…