The length of human pregnancies is approximately normally distributed with mean 266 days and standard deviation 26days. Consider taking samples of size n = 20; thereby, creating a Sampling Distribution.What is the probability that a random sample of 20 pregnancies will have a sample mean length more than 270 days?Use the normal probability graph below to label and shade the picture correctly for this problem.O A. 0.2451O B. 0.7549OC.0.5596O D. 0.4404Save All AnswersSave and SubmiClick Save and Submit to save and submit. Click Save All Answers to save all answers.44°Fe Type here to search1-10/05/17EscCF5FIPrtScF2F3F4F6F7F8InsertDeleteF9F10F11F12&25780BackspaceNumLockETUTabHoreASFGCapsLkD+ IIPCO%#3

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Answered: The length of human pregnancies is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If z is a standard normal variable, find the probability that z is between -2.07 and 3.28
In a certain region, the mean annual salary for electricians is $58,650. Let x be a random variable that represents an electrician's salary. Assume the standard deviation is $1420. If a random sample of 50 electricians is selected, what is the probability that the sample mean is greater than $59,000? A. 0.041 B. 0.403 C. 0.038 D. 0139
The average height of flowering cherry trees in a nursery is 11 feet. If the heights are normally distributed with a standard deviation of 1.6, find the probability that a tree is less than 13 feet tall. O 0.67 0.89 0.95 O 0.78
We are examining farmer production in marginal land. A sample of 100 farmers produce this crop with mean of 100 bushels per acre. Assume a normal distribution. Q1: What is the probability an individual farmer in this population produces 103 or less bushels of corn?Q2: What is the probability the mean bushels of corn produced is 103 or less bushels of corn?
Assume that the time it takes the housekeeping crew of a local hotel to clean a room varies uniformly between 25 and 50 minutes. Calculate the mean and variance for the distribution. Select one: O a. 37.5 and 50.08 O b. 15.5 and 50.08 O c. 51.2 and 36.6 O d. 37.5 and 78.5
Coal is carried from a mine in west virginia to a power plant in new york in hopper cars on a long train. The automatic hopper car loader is set to put 77 tons of coal into each car. The actual weights of coal loaded into each care are normally distributed with mean u= 77 tons and standard deviation 0= 1.1 ton. A. What is the probability that one car chosen at random will have less than 76.5 tons of coal? ( Round your answer to four decimal places.) B. What is the probability that 29 cars chosen at random will have a mean load weight x of less than 76.5 tons of coal? ( Round your answer to four decimal places) C. Suppose the weight of coal in one car was less than 76.5 tons. Would that fact make you suspect that the loader had slipped out of adjustment. Suppose the weight of coal in 29 cars selected at random had an average x of less than 76.5 tons. Would that fact make you suspect that the loader had slipped out of adjustment? Why?
The full height of a certain species of tree has a normal probability distribution with a mean of 195.6 ft and a standard deviation of 7.5 ft. State the random variable. ¯x = the height of a certain species of tree ¯x = the mean height of a certain species of tree x = the height of a certain species of tree x = the diameter of a certain species of tree A tree of this type grows in my backyard, and it stands 187.4 feet tall. Find the probability that the height of a randomly selected tree is shorter than mine. Round to three decimal places.Which is the notation for the probability that the height is shorter than mine? P(x < 187.4) P(¯x < 195.6) P(¯x > 195.6) P(x > 195.6) P(¯x< 187.4) P(x < 195.6)
The NJ Department of Health has reported the average life span of NJ residents is 81 years. If the standard deviation is σ = 4 years, what is the probability of a person living to at least 92 years of age?
The amount of time a marker takes to mark a single Advanced Business Statistics exam script has a normal distribution with mean 336 seconds and standard deviation 198 seconds. One script is selected at random. Find the probability that it takes the marker more than 500 seconds to complete marking this script. A. 0.2033 B. 0.2967 C. 0.7033 D. 0.7967
Given a normal probability distribution with a mean of 9% and a standard deviation of 4%, what is the probability of observing a value between 2% and 14%? Use the following Z-score data is from the HP calculator: Z-Score -2.00 -1.75 -1.50 -1.25 -1.00 0.00 1.00 1.25 1.50 1.75 2.00 Probability 0.0228 0.0401 0.0668 0.1056 0.1587 0.5000 0.8413 0.8944 0.9332 0.9599 0.9772 Answer in decimal format, to 3 decimal places, truncated. For example, if your answer is 33.46%, enter 0.334.
Indrilling a vertical wellbore, the spacing between major fractures are recorded. It has been found that this spacing is having a mean of 180o ft and a variance of 3,240,000 ft In the first 2000 ft drilling, there was no present of major fracture in the well. Determine the probability that there is a major fracture at the depth of 2000-3500 ft. Select one: a.0.57 b.o.43 C. O.19 do 82
In a population of statistics students it was found that the mean score on the final is 150 with a standard deviation of 20 points. Ifa student is chosen at random, what is the probability that their grade will be less than 115? O 03867 O 0.3707 O 0.9599 O 0.5987 O 0.0401

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