**Problem Statement:**The large block shown has dimensions of \( x = 17.0 \, \text{cm} \) wide, \( y = 19.0 \, \text{cm} \) long, and \( z = 29.0 \, \text{cm} \) high with a mass of \( 5.55 \, \text{kg} \). This block is passing through air, which has a density (\( \rho_{\text{air}} \)) of \( 1.43 \, \text{kg/m}^3 \).Calculate the terminal velocity of the block if it is traveling downward with a drag coefficient (\( \Gamma \)) of \( 0.872 \). Refer to the hint panel for the drag force equation.**Diagram Explanation:**The diagram displays a three-dimensional block, presumably a rectangular prism, with labeled dimensions:- \( x \): Width, 17.0 cm- \( y \): Length, 19.0 cm- \( z \): Height, 29.0 cmThere is an arrow indicating downward motion, labeled with velocity \( v \).**Calculation:**Find the terminal velocity of the block. Use the given measurements and conditions in a relevant formula for terminal velocity involving drag force. **Answer Input:**There is a box labeled "terminal velocity" where the calculated value should be entered, in meters per second (m/s).

An object attains terminal velocity when its weight equals the drag force. W=FDmg=12ΓρAv2v=2mgΓρxy

The large block shown is x = 17.0 cm wide, y = 19.0 cm long, and z = 29.00 cm high with a mass of 5.55 kg. This block is passing through air (density of air Pair = 1.43kg/m'). Calculate the terminal velocity of the block if it is traveling downward with a drag coefficient of r 0.872. See the hint panel for the drag force equation. terminal velocity: m/s

The large block shown is x = 17.0 cm wide, y = 19.0 cm long, and z = 29.00 cm high with a mass of 5.55 kg. This block is passing through air (density of air Pair = 1.43kg/m'). Calculate the terminal velocity of the block if it is traveling downward with a drag coefficient of r 0.872. See the hint panel for the drag force equation. terminal velocity: m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

Question

**Problem Statement:**

The large block shown has dimensions of \( x = 17.0 \, \text{cm} \) wide, \( y = 19.0 \, \text{cm} \) long, and \( z = 29.0 \, \text{cm} \) high with a mass of \( 5.55 \, \text{kg} \). This block is passing through air, which has a density (\( \rho_{\text{air}} \)) of \( 1.43 \, \text{kg/m}^3 \).

Calculate the terminal velocity of the block if it is traveling downward with a drag coefficient (\( \Gamma \)) of \( 0.872 \). Refer to the hint panel for the drag force equation.

**Diagram Explanation:**

The diagram displays a three-dimensional block, presumably a rectangular prism, with labeled dimensions:
- \( x \): Width, 17.0 cm
- \( y \): Length, 19.0 cm
- \( z \): Height, 29.0 cm

There is an arrow indicating downward motion, labeled with velocity \( v \).

**Calculation:**

Find the terminal velocity of the block. Use the given measurements and conditions in a relevant formula for terminal velocity involving drag force.

**Answer Input:**

There is a box labeled "terminal velocity" where the calculated value should be entered, in meters per second (m/s).

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