The large block shown is x = 17.0 cm wide, y = 19.0 cm long, and z = 29.00 cm high with a mass of 5.55 kg. This block is passing through air (density of air Pair = 1.43kg/m'). Calculate the terminal velocity of the block if it is traveling downward with a drag coefficient of r 0.872. See the hint panel for the drag force equation. terminal velocity: m/s

College Physics
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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**Problem Statement:**

The large block shown has dimensions of \( x = 17.0 \, \text{cm} \) wide, \( y = 19.0 \, \text{cm} \) long, and \( z = 29.0 \, \text{cm} \) high with a mass of \( 5.55 \, \text{kg} \). This block is passing through air, which has a density (\( \rho_{\text{air}} \)) of \( 1.43 \, \text{kg/m}^3 \).

Calculate the terminal velocity of the block if it is traveling downward with a drag coefficient (\( \Gamma \)) of \( 0.872 \). Refer to the hint panel for the drag force equation.

**Diagram Explanation:**

The diagram displays a three-dimensional block, presumably a rectangular prism, with labeled dimensions:
- \( x \): Width, 17.0 cm
- \( y \): Length, 19.0 cm
- \( z \): Height, 29.0 cm

There is an arrow indicating downward motion, labeled with velocity \( v \).

**Calculation:**

Find the terminal velocity of the block. Use the given measurements and conditions in a relevant formula for terminal velocity involving drag force. 

**Answer Input:**

There is a box labeled "terminal velocity" where the calculated value should be entered, in meters per second (m/s).
Transcribed Image Text:**Problem Statement:** The large block shown has dimensions of \( x = 17.0 \, \text{cm} \) wide, \( y = 19.0 \, \text{cm} \) long, and \( z = 29.0 \, \text{cm} \) high with a mass of \( 5.55 \, \text{kg} \). This block is passing through air, which has a density (\( \rho_{\text{air}} \)) of \( 1.43 \, \text{kg/m}^3 \). Calculate the terminal velocity of the block if it is traveling downward with a drag coefficient (\( \Gamma \)) of \( 0.872 \). Refer to the hint panel for the drag force equation. **Diagram Explanation:** The diagram displays a three-dimensional block, presumably a rectangular prism, with labeled dimensions: - \( x \): Width, 17.0 cm - \( y \): Length, 19.0 cm - \( z \): Height, 29.0 cm There is an arrow indicating downward motion, labeled with velocity \( v \). **Calculation:** Find the terminal velocity of the block. Use the given measurements and conditions in a relevant formula for terminal velocity involving drag force. **Answer Input:** There is a box labeled "terminal velocity" where the calculated value should be entered, in meters per second (m/s).
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