The kinetic energy KE of an object of mass m moving with velocity v is defined as KE =5 mv?. If a force f(x) acts on the object, moving it along the x-axis from x to x2, the Work-Energy Theorem states that the net work done is equal to the change in kinetic energy: mv – mv†, where vi is the velocity at x and v2 is the velocity at x2. (a) Let x = s(t) be the position function of the object at time t and v(t), a(t) the velocity and acceleration func- tions. Prove the Work-Energy Theorem by first using

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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5.4 Problem #31

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(b) part of question asks "Then use Newton's Second Law of Motion (force=mass×acceleration) and the substitution u=v(t) to evaluate the integral

The kinetic energy KE of an object of mass m moving with
velocity v is defined as KE =5 mv?. If a force f(x) acts
on the object, moving it along the x-axis from x to x2, the
Work-Energy Theorem states that the net work done is equal
to the change in kinetic energy: mv – mv†, where vi is
the velocity at x and v2 is the velocity at x2.
(a) Let x = s(t) be the position function of the object at
time t and v(t), a(t) the velocity and acceleration func-
tions. Prove the Work-Energy Theorem by first using
Transcribed Image Text:The kinetic energy KE of an object of mass m moving with velocity v is defined as KE =5 mv?. If a force f(x) acts on the object, moving it along the x-axis from x to x2, the Work-Energy Theorem states that the net work done is equal to the change in kinetic energy: mv – mv†, where vi is the velocity at x and v2 is the velocity at x2. (a) Let x = s(t) be the position function of the object at time t and v(t), a(t) the velocity and acceleration func- tions. Prove the Work-Energy Theorem by first using
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