Part B The tomato is dropped. What is the velocity, v, of the tomato when it hits the ground? Assume 91.9 % of the work done in Part A is transferred to kinetic energy, E, by the time the tomato hits the ground. Express your answer with the appropriate units.

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Part B

**Understanding Energy through a Practical Example**

An object can have two primary types of energy: **kinetic energy**, the energy of motion, and **potential energy**, the energy of position. Energy transfer can occur in various ways, one of which is through work. Work, represented as \( w \), is the energy transferred when an object moves over a distance, \( d \), due to a force, \( F \).

Mathematically,
\[ w = Fd \]

*Force* is determined by the product of an object's mass, \( m \), and its acceleration, \( \alpha \):
\[ F = ma \]

When acceleration is due to gravity, we use \( g \) instead of \( \alpha \), where \( g = 9.81 \, \text{m} \cdot \text{s}^{-2} \).

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**Part A: Calculating Work Done**

**Question:** How much work is done when a 125 g tomato is lifted 13.0 m?

To determine the work done, express your answer with appropriate units.

- **Solution:** \( w = 15.9 \, \text{J} \)

This indicates that 15.9 joules of energy is transferred to the tomato, increasing its potential energy as it is elevated above the ground.

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**Kinetic Energy**

*Kinetic energy*, \( E_k \), is calculated using the formula:
\[ E_k = \frac{1}{2} mv^2 \]
where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second.

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**Part B: Determining Velocity upon Impact**

**Scenario:** If the tomato is dropped, what is its velocity when it reaches the ground? Assume 91.9% of the work calculated in Part A is converted to kinetic energy, \( E_k \).

Provide your answer with appropriate units.
Transcribed Image Text:**Understanding Energy through a Practical Example** An object can have two primary types of energy: **kinetic energy**, the energy of motion, and **potential energy**, the energy of position. Energy transfer can occur in various ways, one of which is through work. Work, represented as \( w \), is the energy transferred when an object moves over a distance, \( d \), due to a force, \( F \). Mathematically, \[ w = Fd \] *Force* is determined by the product of an object's mass, \( m \), and its acceleration, \( \alpha \): \[ F = ma \] When acceleration is due to gravity, we use \( g \) instead of \( \alpha \), where \( g = 9.81 \, \text{m} \cdot \text{s}^{-2} \). --- **Part A: Calculating Work Done** **Question:** How much work is done when a 125 g tomato is lifted 13.0 m? To determine the work done, express your answer with appropriate units. - **Solution:** \( w = 15.9 \, \text{J} \) This indicates that 15.9 joules of energy is transferred to the tomato, increasing its potential energy as it is elevated above the ground. --- **Kinetic Energy** *Kinetic energy*, \( E_k \), is calculated using the formula: \[ E_k = \frac{1}{2} mv^2 \] where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second. --- **Part B: Determining Velocity upon Impact** **Scenario:** If the tomato is dropped, what is its velocity when it reaches the ground? Assume 91.9% of the work calculated in Part A is converted to kinetic energy, \( E_k \). Provide your answer with appropriate units.
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