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Grandpa stills plays his old 78's on an antique Victrola. If the records are 10.0 inches in diameter and the 78 refers to the number of revolutions per minute, what is the centripetal acceleration (in m/s?) of a dust particle on the edge of a rotating record? (Hint: 1 revolution = 1 cycle = 1 circumference of travel) Use: 1.00 inch = 2.54 cm (exact)

Grandpa stills plays his old 78's on an antique Victrola. If the records are 10.0 inches in diameter and the 78 refers to the number of revolutions per minute, what is the centripetal acceleration (in m/s?) of a dust particle on the edge of a rotating record? (Hint: 1 revolution = 1 cycle = 1 circumference of travel) Use: 1.00 inch = 2.54 cm (exact)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Grandpa stills plays his old 78's on an antique Victrola. If the records are 10.0 inches in diameter and the 78 refers to the number of revolutions per minute, what is the centripetal acceleration (in m/s?) of a dust particle on the edge of a rotating record? (Hint: 1 revolution = 1 cycle = 1 circumference of travel) Use: 1.00 inch = 2.54 cm (exact)
Transcribed Image Text:Grandpa stills plays his old 78's on an antique Victrola. If the records are 10.0 inches in diameter and the 78 refers to the number of revolutions per minute, what is the centripetal acceleration (in m/s?) of a dust particle on the edge of a rotating record? (Hint: 1 revolution = 1 cycle = 1 circumference of travel) Use: 1.00 inch = 2.54 cm (exact)
Expert Solution
Step 1 Formula

Formula of centripetal acceleration is as follows;

ac=ω2r                                                            1)where,r=radius of circleω=angular speed

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