The Keq for the reaction of water with water is called Kw H₂O + H₂O → H3O+1 + OH-1 [H3O+¹][OH-¹] Kw [H3O+¹][OH-¹] = (1 x 10-7)² = 1 x 10-14 [H₂O]² The inverse logarithm, or -log, of [H3O+¹][OH-¹] = 10-14 is pH + pOH = 14 1. What happens to the [H3O+¹] when acid is added to neutral water? the [H3O+¹] goes 2. What happens to the pH when acid is added to neutral water? an example of an increased [H3O+¹] is [H3O+¹] = 1 x 10-6. Thus pH = -log[106] = 6 thus, adding acid makes the pH go 3. What happens to the [OH-¹] when acid is added to neutral water ? in the equation [H3O+¹][OH-¹] = 10-14, when [H3O+¹] increases, the [OH-¹] goes

The Keq for the reaction of water with water is called Kw H₂O + H₂O → H3O+1 + OH-1 [H3O+¹][OH-¹] Kw [H3O+¹][OH-¹] = (1 x 10-7)² = 1 x 10-14 [H₂O]² The inverse logarithm, or -log, of [H3O+¹][OH-¹] = 10-14 is pH + pOH = 14 1. What happens to the [H3O+¹] when acid is added to neutral water? the [H3O+¹] goes 2. What happens to the pH when acid is added to neutral water? an example of an increased [H3O+¹] is [H3O+¹] = 1 x 10-6. Thus pH = -log[106] = 6 thus, adding acid makes the pH go 3. What happens to the [OH-¹] when acid is added to neutral water ? in the equation [H3O+¹][OH-¹] = 10-14, when [H3O+¹] increases, the [OH-¹] goes

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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