The joint probability mass function of X and Y is given byp(1, 1) = 0.4p(1, 2) = 0.1p(1,3) = 0.05p(2, 1) = 0.05 p(2, 2) = 0.05 p(2,3) = 0.05p(3, 2) = 0.1p(3, 1) = 0.1p(3,3) = 0.1(a) Compute the conditional mass function of Y given X = 3: P(Y = 1|X = 3) =P(Y = 2|X = 3) =%3DP(Y = 3|X = 3) =(b) Are X and Y independent? (enter YES or NO)(c) Compute the following probabilities:P(X+Y > 2) =%3DP(XY = 2) =P(주> 1) =%3D The distribution of heights of adult men in the U.S. is approximately normal with mean 69inches and standard deviation 2.5 inches. Use what you know about a normal distribution and the 68-95-99.7 rule to answer the questions in parts (a),(b),(c) below.Your answer must be entered in the correct format. If your answer is a percent, such as 25 percent,enter: "25 PERCENT" (without the quotes). If your answer is in inches, such as 10 inches, enter: "10INCHES" (without the quotes and with a space between the number and the INCHES). If your answeris an interval, such as 14 to 15 inches, then enter: "14 TO 15 INCHES" (without the quotes). Don'treport accuracy greater than what comes from the 68-95-99.7 rule! For example, if the rule says"10 INCHES then "10.0 INCHES" is wrong because the extra decimal place claims too muchaccuracy. If the rule says "1.2 INCHES" then "1.20 INCHES" is wrong.(a) About what percent of men are between 69 and 74 inches?Answer: .48(b) Fill in the blank: About 2.5 percent of all men are shorter thanAnswer: .67(c) About what percent of men are taller than 69 inches?Answer: 1/2

As per policy I can answer the first three part of question. So for more remaining answer please…

The joint probability mass function of X and Y is given by p(1, 1) = 0.4 p(1,2) = 0.1 p(1,3) = 0.05 p(2, 1) = 0.05 p(2, 2) = 0.05 p(2, 3) = 0.05 p(3, 1) = 0.1 p(3, 2) = 0.1 p(3, 3) = 0.1 (a) Compute the conditional mass function of Y given X = 3: P(Y = 1|X = 3) = %3D P(Y = 2|X = 3) = %3D P(Y = 3|X = 3) = (b) Are X and Y independent? (enter YES or NO) (c) Compute the following probabilities: P(X+Y > 2) = %3D P(XY = 2) = P(주 > 1) =

The joint probability mass function of X and Y is given by p(1, 1) = 0.4 p(1,2) = 0.1 p(1,3) = 0.05 p(2, 1) = 0.05 p(2, 2) = 0.05 p(2, 3) = 0.05 p(3, 1) = 0.1 p(3, 2) = 0.1 p(3, 3) = 0.1 (a) Compute the conditional mass function of Y given X = 3: P(Y = 1|X = 3) = %3D P(Y = 2|X = 3) = %3D P(Y = 3|X = 3) = (b) Are X and Y independent? (enter YES or NO) (c) Compute the following probabilities: P(X+Y > 2) = %3D P(XY = 2) = P(주 > 1) =

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

The joint probability mass function of X and Y is given by
p(1, 1) = 0.4
p(1, 2) = 0.1
p(1,3) = 0.05
p(2, 1) = 0.05 p(2, 2) = 0.05 p(2,3) = 0.05
p(3, 2) = 0.1
p(3, 1) = 0.1
p(3,3) = 0.1
(a) Compute the conditional mass function of Y given X = 3: P(Y = 1|X = 3) =
P(Y = 2|X = 3) =
%3D
P(Y = 3|X = 3) =
(b) Are X and Y independent? (enter YES or NO)
(c) Compute the following probabilities:
P(X+Y > 2) =
%3D
P(XY = 2) =
P(주> 1) =
%3D

The distribution of heights of adult men in the U.S. is approximately normal with mean 69
inches and standard deviation 2.5 inches. Use what you know about a normal distribution and the 68-
95-99.7 rule to answer the questions in parts (a),(b),(c) below.
Your answer must be entered in the correct format. If your answer is a percent, such as 25 percent,
enter: "25 PERCENT" (without the quotes). If your answer is in inches, such as 10 inches, enter: "10
INCHES" (without the quotes and with a space between the number and the INCHES). If your answer
is an interval, such as 14 to 15 inches, then enter: "14 TO 15 INCHES" (without the quotes). Don't
report accuracy greater than what comes from the 68-95-99.7 rule! For example, if the rule says
"10 INCHES then "10.0 INCHES" is wrong because the extra decimal place claims too much
accuracy. If the rule says "1.2 INCHES" then "1.20 INCHES" is wrong.
(a) About what percent of men are between 69 and 74 inches?
Answer: .48
(b) Fill in the blank: About 2.5 percent of all men are shorter than
Answer: .67
(c) About what percent of men are taller than 69 inches?
Answer: 1/2

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