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The joint probability mass function of X and Y is given by p(1, 1) — 0.35 p(1, 2) — 0.05 р(1,3) — 0.05 p(2, 1) = 0.05 p(2,2) = 0 p(3, 1) = 0.1 p(2, 3) = 0.1 p(3, 2) = 0.05 p(3,3) = 0.25 (a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) = %3D P(Y = 2|X = 2) = P(Y = 3|X = 2) = %3D (b) Are X and Y independent? (enter YES or NO)

The joint probability mass function of X and Y is given by p(1, 1) — 0.35 p(1, 2) — 0.05 р(1,3) — 0.05 p(2, 1) = 0.05 p(2,2) = 0 p(3, 1) = 0.1 p(2, 3) = 0.1 p(3, 2) = 0.05 p(3,3) = 0.25 (a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) = %3D P(Y = 2|X = 2) = P(Y = 3|X = 2) = %3D (b) Are X and Y independent? (enter YES or NO)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The joint probability mass function of X and Y is given by p(1,1) = 0.35 p(1,2) = 0.05 p(1,3) = 0.05 p(2,1) = 0.05 p(2,2) = 0 Р(3, 1) — 0.1 p(2,3) = 0.1 p(3, 2) = 0.05 p(3,3) = 0.25 (a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) P(Y = 2|X = 2) = P(Y = 3|X = 2) = (b) Are X and Y independent? (enter YES or NO)
Transcribed Image Text:The joint probability mass function of X and Y is given by p(1,1) = 0.35 p(1,2) = 0.05 p(1,3) = 0.05 p(2,1) = 0.05 p(2,2) = 0 Р(3, 1) — 0.1 p(2,3) = 0.1 p(3, 2) = 0.05 p(3,3) = 0.25 (a) Compute the conditional mass function of Y given X = 2: P(Y = 1|X = 2) P(Y = 2|X = 2) = P(Y = 3|X = 2) = (b) Are X and Y independent? (enter YES or NO)
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