The joint distribution of X and Y is: Рxp(0,0)-1/10, Рҳr(0,1)-а, Рxx(0,2)-2/10 Pxy(1,0)=a, Pxy(1,1)=b, Pxy(1,2)=a Pxy(2,0)=2/10, Pxy(2,1)=a, Pxy(2,2)=1/10 P. P. You want "a" to make the variance of Y as minimum as possible. The variance of Y equals. Select one: а. 6/25 3 b. 3/10 С. 2/5 d. 3/5 e. 1/2
The joint distribution of X and Y is: Рxp(0,0)-1/10, Рҳr(0,1)-а, Рxx(0,2)-2/10 Pxy(1,0)=a, Pxy(1,1)=b, Pxy(1,2)=a Pxy(2,0)=2/10, Pxy(2,1)=a, Pxy(2,2)=1/10 P. P. You want "a" to make the variance of Y as minimum as possible. The variance of Y equals. Select one: а. 6/25 3 b. 3/10 С. 2/5 d. 3/5 e. 1/2
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![The joint distribution of X and Y is:
Рxp(0,0)-1/10, Рҳr(0,1)-а, Рxx(0,2)-2/10
Pxy(1,0)=a, Pxy(1,1)=b, Pxy(1,2)=a
Pxy(2,0)=2/10, Pxy(2,1)=a, Pxy(2,2)=1/10
P.
P.
You want "a" to make the variance of Y as minimum as possible.
The variance of Y equals.
Select one:
а. 6/25
3
b. 3/10
С. 2/5
d. 3/5
e. 1/2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0956c8a5-08a3-45de-894e-83fc31af31be%2F8695ae14-77b6-4881-847c-06dc01a6b67d%2Fcbj5fv_processed.png&w=3840&q=75)
Transcribed Image Text:The joint distribution of X and Y is:
Рxp(0,0)-1/10, Рҳr(0,1)-а, Рxx(0,2)-2/10
Pxy(1,0)=a, Pxy(1,1)=b, Pxy(1,2)=a
Pxy(2,0)=2/10, Pxy(2,1)=a, Pxy(2,2)=1/10
P.
P.
You want "a" to make the variance of Y as minimum as possible.
The variance of Y equals.
Select one:
а. 6/25
3
b. 3/10
С. 2/5
d. 3/5
e. 1/2
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