The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker. IO3(aq) + 5I–(aq) + 6H+(aq) → 3I2(aq) + 3H2O(l) I2(aq) + 2S2O32–(aq) → 2I–(aq) + S4O62–(aq) The molecular iodine (I2) formed in reaction 1 is immediately used up in reaction 2, so that no iodine accumulates. In one experiment, a student made up a reaction mixture which initially contained 0.0020 mol of iodate ions (IO3−). If the iodate ions reacted completely, how many moles of thiosulfate ions (S2O32−) were needed in reaction 2, in order to react completely with the iodine (I2) produced in reaction 1?

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The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker.


IO3(aq) + 5I(aq) + 6H+(aq) → 3I2(aq) + 3H2O(l)


I2(aq) + 2S2O32–(aq) → 2I(aq) + S4O62–(aq)


The molecular iodine (I2) formed in reaction 1 is immediately used up in reaction 2, so that no iodine accumulates. In one experiment, a student made up a reaction mixture which initially contained 0.0020 mol of iodate ions (IO3). If the iodate ions reacted completely, how many moles of thiosulfate ions (S2O32−) were needed in reaction 2, in order to react completely with the iodine (I2) produced in reaction 1?

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