The Intermediate Value Theorem can be used to approximate a root. The following is an example of binary search in computer science. Suppose you want to approximate v7. You know that it is between 2 and 3. If you consider the function f(x) = x - 7, then note that f(2) < 0 and f(3) > 0. Therefore by the Intermediate Value Theorem, there is a value, 2

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Chapter2: Second-order Linear Odes
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The Intermediate Value Theorem can be used to approximate a root. The following is an example of binary search in computer science. Suppose you want to approximate √7. You know that it is between 2 and 3. If you consider the function \( f(x) = x^2 - 7 \), then note that \( f(2) < 0 \) and \( f(3) > 0 \). Therefore by the Intermediate Value Theorem, there is a value, \( 2 \leq c \leq 3 \) such that \( f(c) = 0 \). Next, choose the midpoint of these two values, 2.5, which is guaranteed to be within 0.5 of the actual root. \( f(2.5) \) will either be less than 0 or greater than 0. You can use the Intermediate Value Theorem again replacing 2.5 with the previous endpoint that has the same sign as 2.5. Continuing this process gives a sequence of approximations \( x_n \) with \( x_1 = 2.5 \). How many iterations must you do in order to be within 0.001953125 of the root?
Transcribed Image Text:The Intermediate Value Theorem can be used to approximate a root. The following is an example of binary search in computer science. Suppose you want to approximate √7. You know that it is between 2 and 3. If you consider the function \( f(x) = x^2 - 7 \), then note that \( f(2) < 0 \) and \( f(3) > 0 \). Therefore by the Intermediate Value Theorem, there is a value, \( 2 \leq c \leq 3 \) such that \( f(c) = 0 \). Next, choose the midpoint of these two values, 2.5, which is guaranteed to be within 0.5 of the actual root. \( f(2.5) \) will either be less than 0 or greater than 0. You can use the Intermediate Value Theorem again replacing 2.5 with the previous endpoint that has the same sign as 2.5. Continuing this process gives a sequence of approximations \( x_n \) with \( x_1 = 2.5 \). How many iterations must you do in order to be within 0.001953125 of the root?
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