The integral -dz (81-22)를 can be reduced to the form k sin" (0) cos" (0) de, with the substitution z(e) = 9*sin(theta) so that, in terms of 0, V81 – 22 9*cos(theta) 2 0, k = 1/9 m =3 and n =-4 The substitution u(0): reduces the integral to S R(u) du, where the rational function R(u) = The partial fraction expansion of R(u) is The integral S R(u) du = from which we see that (81 – 2) = rp

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A: Given : ∫4sec611xdx

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A:

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A: We have to solve the integral

Q: Compute the following integral: / secʻ(5x) tan" (5x) de 1 (tan(5x))*+3 + C 1 а) 5R + 5 (tan(5x))*+1…

A: We can solve this by using some basic concept of integration as substitution method .

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A:

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A: Apply integration by parts

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A:

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A: