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The instructions below were run within a matlab/octave command window. Determine the value of the variable my_val_2 then enter your answer in the field below (enter a numerical value only) my_val_2=1.4; my_val_2=6.6; my_val_2=9; %c= my_val_2-b;

The instructions below were run within a matlab/octave command window. Determine the value of the variable my_val_2 then enter your answer in the field below (enter a numerical value only) my_val_2=1.4; my_val_2=6.6; my_val_2=9; %c= my_val_2-b;

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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The instructions below were run within a matlab/octave command window. Determine the value of the variable my_val_2 then enter your answer in the field below (enter a numerical value only) my_val_2=1.4; my_val_2=6.6; my_val_2=9; %c= my_val_2-b;
Transcribed Image Text:The instructions below were run within a matlab/octave command window. Determine the value of the variable my_val_2 then enter your answer in the field below (enter a numerical value only) my_val_2=1.4; my_val_2=6.6; my_val_2=9; %c= my_val_2-b;
Expert Solution
Explanation

1) Instructions as in question updates the value of variables my_val_2 multiples times

  • It uses assignment operator and update the value of my_val_2 three times as below
    • my_val_2 = 1.4;
    • my_val_2 = 6.6;
    • my_val_2 = 9;
  • So after third statement gets executed final value of variable my_val_2 is 9

2) Last instruction calculates the difference between my_val_2 and variable b and assign it to variable c

  • %c = my_val_2 - b; 
  • % indicates this operation is commented out so it will not execute after first three statements

3) So final value of my_val_2 is 9

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