The inside diameter of a randomly selected piston ring is a random variable with mean value 14 cm and standard deviation 0.05 cm. Suppose the distribution of the diameter is normal. (Round your answers to four decimal places.) n USE SALT (a) Calculate P(13.99 < X s 14.01) when n = 16. P(13.99 s Xs 14.01) = 0.5437 (b) How likely is it that the sample mean diameter exceeds 14.01 whenn = 25? P(X 2 14.01) = 0.2271

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The inside diameter of a randomly selected piston ring is a random variable with mean value 14 cm and standard deviation 0.05 cm. Suppose the distribution of the diameter is normal.
(Round your answers to four decimal places.)
n USE SALT
(a) Calculate P(13.99 < X < 14.01) when n = 16.
P(13.99 < X < 14.01) = 0.5437
(b) How likely is it that the sample mean diameter exceeds 14.01 when n = 25?
P(X > 14.01) = 0.2271
You may need to use the appropriate table in the Appendix of Tables to answer this question.
Transcribed Image Text:The inside diameter of a randomly selected piston ring is a random variable with mean value 14 cm and standard deviation 0.05 cm. Suppose the distribution of the diameter is normal. (Round your answers to four decimal places.) n USE SALT (a) Calculate P(13.99 < X < 14.01) when n = 16. P(13.99 < X < 14.01) = 0.5437 (b) How likely is it that the sample mean diameter exceeds 14.01 when n = 25? P(X > 14.01) = 0.2271 You may need to use the appropriate table in the Appendix of Tables to answer this question.
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