The initial voltage across the inductor, and current running through the inductor, are both zero. If the current for time greater than zero is i(t) = 10texp(-5t) [A], the voltage potential across the inductor is V(t) = exp(-5t) (1 - 5t) [V], and the inductance is 0.1 [H], select the correct expression for the power delivered to the inductor: a) 10texp(-5t) - 50(t²)exp(-5t) [J] b) 10texp(-10t) - 50(t²)exp(-10t) [J] c) 10texp(-5t) - 50(1²)exp(-5t) [W] d) 10texp(-10t) - 50(t²)exp(-10t) [W] e) 10texp(-10t) - 50(t²)exp(-10t) [J] f) None of the above

The initial voltage across the inductor, and current running through the inductor, are both zero. If the current for time greater than zero is i(t) = 10texp(-5t) [A], the voltage potential across the inductor is V(t) = exp(-5t) (1 - 5t) [V], and the inductance is 0.1 [H], select the correct expression for the power delivered to the inductor: a) 10texp(-5t) - 50(t²)exp(-5t) [J] b) 10texp(-10t) - 50(t²)exp(-10t) [J] c) 10texp(-5t) - 50(1²)exp(-5t) [W] d) 10texp(-10t) - 50(t²)exp(-10t) [W] e) 10texp(-10t) - 50(t²)exp(-10t) [J] f) None of the above

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

HVDC

HVDC stands for high voltage direct current in the electric power transmission system. The high voltage direct current system uses direct current (DC) for the transmission of electrical power through transmission lines in contrast with the alternating current that is the AC system. The HVDC is used to transmit bulk power point-to-point through long distances transmission lines. Power is rapidly transferred because the efficiency of transmission lines is greatly increased over long distances due to HVDC lines.

Question

The initial voltage across the inductor, and current running through the inductor, are both
zero. If the current for time greater than zero is i(t) = 10texp(-5t) [A], the voltage potential
across the inductor is V(t) = exp(-5t) (1 – 5t) [V], and the inductance is 0.1 [H], select the
correct expression for the power delivered to the inductor:
a) 10texp(-5t) - 50(t²)exp(-5t) [J]
b) 10texp(-10t) - 50(t²)exp(-10t) [J]
c) 10texp(-5t) - 50(1²)exp(-5t) [W]
d) 10texp(-10t) - 50(t²)exp(-10t) [W]
e) 10texp(-10t) - 50(t²)exp(-10t) [J]
f) None of the above
MMINI

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