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The inequality V4-x-2 0 that places the centered interval (-6,6) inside the interval (-4e-e,4e-e). Take & to be the distance from c= 0 to the nearer endpoint of (-4e-24e-e). 8= min {l0- (-4e-2)|.|0- (4e-2) |} 6=min{|4e + 2리1-4e + 2}

The inequality V4-x-2 0 that places the centered interval (-6,6) inside the interval (-4e-e,4e-e). Take & to be the distance from c= 0 to the nearer endpoint of (-4e-24e-e). 8= min {l0- (-4e-2)|.|0- (4e-2) |} 6=min{|4e + 2리1-4e + 2}

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The inequality V4-x-2 <e holds for all x#0 in the open interval (- 4e -e,4e-e). Now, find a value of 8>0 that places the centered interval (-6,6) inside the interval (-4e-e,4e-e). Take & to be the distance from c= 0 to the nearer endpoint of (-4e-24e-e). 8= min {l0- (-4e-2)|.|0- (4e-2) |} 6=min{|4e + 2리1-4e + 2}
Transcribed Image Text:The inequality V4-x-2 <e holds for all x#0 in the open interval (- 4e -e,4e-e). Now, find a value of 8>0 that places the centered interval (-6,6) inside the interval (-4e-e,4e-e). Take & to be the distance from c= 0 to the nearer endpoint of (-4e-24e-e). 8= min {l0- (-4e-2)|.|0- (4e-2) |} 6=min{|4e + 2리1-4e + 2}
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